c++实现语音识别问题求解

#include <iostream>
#include <unordered_map>
#include <vector>

using namespace std;

// 建立数字和拼音的映射表
unordered_map<int, string> dict = {
    {0, "ling"},
    {1, "yi"},
    {2, "er"},
    {3, "san"},
    {4, "si"},
    {5, "wu"},
    {6, "liu"},
    {7, "qi"},
    {8, "ba"},
    {9, "jiu"}
};

// 建立十位数字和拼音的映射表
unordered_map<int, string> tenDigit = {
    {1, "shi"},
    {2, "er shi"},
    {3, "san shi"},
    {4, "si shi"},
    {5, "wu shi"},
    {6, "liu shi"},
    {7, "qi shi"},
    {8, "ba shi"},
    {9, "jiu shi"}
};

// 建立百位数字和拼音的映射表
unordered_map<int, string> hundredDigit = {
    {1, "yi bai"},
    {2, "er bai"},
    {3, "san bai"},
    {4, "si bai"},
    {5, "wu bai"},
    {6, "liu bai"},
    {7, "qi bai"},
    {8, "ba bai"},
    {9, "jiu bai"}
};

// 将拼音转换为数字
int convertToNumber(string pinyin) {
    int num = 0;
    for (auto it : dict) {
        if (it.second == pinyin) {
            num = it.first;
            break;
        }
    }
    return num;
}

// 实现语音识别的函数
int speechToNumber(string speech) {
    int number = 0;
    int len = speech.length();
    int idx = 0;
    while (idx < len) {
        int digit = 0;  // 当前位的数字
        string pinyin = "";  // 当前位的拼音

        if (speech[idx] == 'l') {  // 处理"ling"
            pinyin = "ling";
            digit = convertToNumber(pinyin);
            idx += 4;
        } else if (speech[idx] == 'y') {  // 处理"yi"
            if (idx + 1 < len && speech[idx + 1] == 'i') { // 处理"yi"
                pinyin = "yi";
                digit = convertToNumber(pinyin);
                idx += 2;
            } else {  // 处理"yin"
                pinyin = "shi";
                digit = convertToNumber(pinyin);
                idx += 3;
            }
        } else if (speech[idx] == 'e') {  // 处理"er"
            pinyin = "er";
            digit = convertToNumber(pinyin);
            idx += 2;
        } else {  // 处理其他数字的拼音
            pinyin = speech.substr(idx, 3);
            digit = convertToNumber(pinyin);
            idx += 3;
        }

        // 判断当前位的十位和个位
        int ten = 0;
        int unit = 0;

        if (idx < len && speech[idx] == 's') {  // 处理十位
            string tenPinyin = pinyin + " shi";
            ten = convertToNumber(tenPinyin);
            idx += 3;
        }

        if (idx < len && speech[idx] != 'l') {  // 处理个位
            string unitPinyin = speech.substr(idx, 3);
            unit = convertToNumber(unitPinyin);
            idx += 3;
        } else if (ten != 0) {
            unit = 0;  // 十位不为零时，个位为零
            idx += 4;
        }

        // 计算当前位的数字
        int currDigit = digit * 10 + ten + unit;

        // 处理百位
        if (idx < len && speech[idx] == 'b') {
            string hundredPinyin = pinyin + " bai";
            int hundred = convertToNumber(hundredPinyin);
            currDigit = hundred * 100 + currDigit;
            idx += 5;
        }

        // 将当前位的数字累加
        number = number * 1000 + currDigit;
    }
    return number;
}

int main() {
    string speech;
    cin >> speech;
    int number = speechToNumber(speech);
    cout << number << endl;
    return 0;
}