acm竞赛题型探讨询问贴

小女不才，想问下大家acm比赛题目。下面是完整的题目，近年来研一计算机与技术作为比赛入门题目，已经有big牛解答出来了，不知道这位夜深人静的用户能提出完整的解答思路吗，让小女跟师兄们宣传下您的技术。提前感谢哦。

Description
We are not alone.
In the year 3000, scientists have eventually found another planet which has intelligent
being living on. Let's say, Planet X. And we call the intelligent being there 'XMen'. To
learn advanced technology from Planet X, we want to exchange information with
XMen. Unfortunately, XMen use a very strange data format when sending message,
which is called m-encoding (m is for multiplication). Scientists on earth have
successfully found out the algorithm of m-encoding, defining as following:
For each data package from XMen, there are two non-negative integer numbers, A
and B. And the actual data XMen want to send is the product of A and B (A * B).
So, in this problem, you are to implement a decoder for data packages from XMen.

Input
There are multiple test cases. Input data starts with an integer N, indicating the
number of test cases. Each test case occupies just one line, and contains two
non-negative integers A and B (0 <= A, B <= 10的1000000次方)(这里本来100000在10的右上方指数位置,但是贴过来变成一行了,所以我改成这样) separated by just one space.

Output
For each test case, output the actual data XMen want to send, one in a line.
Sample Input
3
1 1
100 123
12345678901234567890 54321
Sample Output
1
12300
670629623593962962352690


Problem Statement 

      A simple line drawing program uses a blank 20 x 20 pixel canvas and a directional cursor that starts at the upper left corner pointing straight down. The upper left corner of the canvas is at (0, 0) and the lower right corner is at (19, 19). You are given a string[], commands, each element of which contains one of two possible commands. A command of the form "FORWARD x" means that the cursor should move forward by x pixels. Each pixel on its path, including the start and end points, is painted black. The only other command is "LEFT", which means that the cursor should change its direction by 90 degrees counterclockwise. So, if the cursor is initially pointing straight down and it receives a single "LEFT" command, it will end up pointing straight to the right. Execute all the commands in order and return the resulting 20 x 20 pixel canvas as a string[] where character j of element i represents the pixel at (i, j). Black pixels should be represented as uppercase 'X' characters and blank pixels should be represented as '.' characters. 

Definition 

      Class:  DrawLines 

Method:  execute 

Parameters:  string[] 

Returns:  string[] 

Method signature:  string[] execute(string[] commands) 

(be sure your method is public) 

 

     

 

Notes 

-  The cursor only paints the canvas if it moves (see example 1). 

Constraints 

-  commands will contain between 1 and 50 elements, inclusive. 

-  Each element of commands will be formatted as either "LEFT" or "FORWARD x" (quotes for clarity only), where x is an integer between 1 and 19, inclusive, with no extra leading zeros. 

-  When executing the commands in order, the cursor will never leave the 20 x 20 pixel canvas. 

【以下回答由 GPT 生成】

解决方案如下:

1. 首先，我们需要读取输入数据中的测试用例数量 N。

2. 然后，我们需要使用循环来处理每个测试用例。

3. 对于每个测试用例, 我们需要读取两个非负整数 A 和 B。

4. 接下来，我们将 A 和 B 相乘得到结果 C。

5. 最后，将结果 C 输出到标准输出流中，并换行。

具体代码如下:

def decode_data():
    # 读取测试用例数量
    N = int(input())

    # 处理每个测试用例
    for _ in range(N):
        # 读取 A 和 B
        A, B = map(int, input().split())

        # 计算 C
        C = A * B

        # 输出 C
        print(C)

decode_data()

以上代码使用了Python来解决该问题。您可以根据需要选择其他编程语言来实现相同的逻辑。

请注意, 上述代码假设输入数据是按照题目要求进行格式化的，并且没有错误情况。如有需要, 您可以添加错误处理代码来处理异常情况。

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