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Magical Series
In this task, we need to check whether a given series is a Magical Series.
A magical series of size n is a permutation of integers [0, n-1] such that the differences between adjacent integers are a permutation of [1, n-1].
Example:
Consider a series of 6 integers (4, 2, 3, 0, 5, 1). As we can see from the above figure, the differences between adjacent integers are a permutation of [1, 5]. So, this is a Magical Series of size 6.
Input:
The input will have 2 lines.
First line contains the size (N) of a series and
The second line contains a series of N integers.
Output:
The first line must contain a positive non-zero integer, N > 1. If not, print "Error in input" and quit the program.
The second line must contain exactly N non-negative integers. If not, print "Invalid input" and quit the program.
After making sure the inputs are valid, check whether the given series satisfies all the conditions of a magical series.
If yes, print "It is a Magical Series".
Otherwise print "It is not a Magical Series".
Sample Input1:
6
4 2 3 0 5 1
Sample output1:
It is a Magical Series
Sample Input2:
11
3 7 4 6 5 0 10 1 9 2 8
Sample output2:
It is a Magical Series
Sample Input3:
-3
0 1 3
Sample output3:
Error in input
Sample Input4:
3
0 -1 3
Sample output4:
Invalid input
Sample Input5:
6
5 0 4 3 1 2
Sample output5:
It is not a Magical Series
【以下回答由 GPT 生成】
首先,我们看到输入包含两行内容,第一行是一个正整数N,表示序列的长度,第二行是N个非负整数,表示序列中的元素。
我们可以按照以下步骤来解决这个问题:
import java.util.Scanner;
// 读取输入
Scanner scanner = new Scanner(System.in);
int N = scanner.nextInt();
scanner.nextLine(); // 清空输入缓冲区
String[] input = scanner.nextLine().split(" ");
// 将字符串数组解析为整数数组
int[] sequence = new int[N];
for (int i = 0; i < N; i++) {
sequence[i] = Integer.parseInt(input[i]);
}
// 检查输入的有效性
if (N <= 1) {
System.out.println("Error in input");
System.exit(0);
}
for (int i = 0; i < N; i++) {
if (sequence[i] < 0) {
System.out.println("Invalid input");
System.exit(0);
}
}
boolean isValid = true;
for (int i = 0; i < N-1; i++) {
int diff = Math.abs(sequence[i] - sequence[i+1]);
if (diff < 1 || diff > N-1) {
isValid = false;
break;
}
}
if (isValid) {
System.out.println("It is a Magical Series");
} else {
System.out.println("It is not a Magical Series");
}
完整的代码如下所示:
import java.util.Scanner;
public class MagicalSeries {
public static void main(String[] args) {
// 读取输入
Scanner scanner = new Scanner(System.in);
int N = scanner.nextInt();
scanner.nextLine(); // 清空输入缓冲区
String[] input = scanner.nextLine().split(" ");
// 将字符串数组解析为整数数组
int[] sequence = new int[N];
for (int i = 0; i < N; i++) {
sequence[i] = Integer.parseInt(input[i]);
}
// 检查输入的有效性
if (N <= 1) {
System.out.println("Error in input");
System.exit(0);
}
for (int i = 0; i < N; i++) {
if (sequence[i] < 0) {
System.out.println("Invalid input");
System.exit(0);
}
}
// 检查魔法序列的条件
boolean isValid = true;
for (int i = 0; i < N-1; i++) {
int diff = Math.abs(sequence[i] - sequence[i+1]);
if (diff < 1 || diff > N-1) {
isValid = false;
break;
}
}
// 输出结果
if (isValid) {
System.out.println("It is a Magical Series");
} else {
System.out.println("It is not a Magical Series");
}
}
}
希望这个解决方案对你有帮助!如果你有任何问题,请随时提问。
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