就是插入一个循环没有任何反应，请问这是为什么，该怎么改
#include <ny8.h>
#include "ny8_constant.h"
#define UPDATE_REG(x) __asm__("MOVR _" #x ",F")
void delay(void)
{
unsigned char i,j;
for(i=5;i>0;i--)
for(j=100;j>0;j--);
}
//! interrupt service routine
void isr(void) __interrupt(1)
{
if(INTFbits.T1IF)
{
PORTB ^= (1<<1); // PB1 Toggle
INTF= (unsigned char)~(C_INT_TMR1); // Clear T1IF flag bit
}
if(INTFbits.T0IF)
{
PORTB ^= 1; // PB0 Toggle
INTF= (unsigned char)~(C_INT_TMR0); // Clear T0IF flag bit
}
if(INTFbits.WDTIF)
{
PORTB ^= (1<<2); // PB2 Toggle
INTF= (unsigned char)~(C_INT_WDT); // Clear WDTIF flag bit
}
}
void main(void)
{
unsigned char R_shift_regl = 0xFF;
//;Initial GPIO
IOSTB = C_PB5_Input | C_PB4_Input | C_PB3_Input; // Set PB0 & PB1 to input mode,others set to output mode
PORTB = 0x07; // PB0、PB1 & PB2 are output High
DISI();
//;Initial Timer0
PCON1 = C_TMR0_Dis; // Disable Timer0
TMR0 = 0; // Load 0x00 to TMR0 (Initial Timer0 register)
T0MD = C_PS0_TMR0 | C_PS0_Div8 ; // Prescaler0 is assigned to Timer0, Prescaler0 dividing rate = 1:8,clock source is instruction clock
//;--Initial WDT (if WDT needs prescaler0 dividing rate )--------------------------------------------------
// T0MD = C_PS0_WDT // Prescaler0 is assigned to WDT, Prescaler0 dividing rate = 1:2 (WDT select interrupt)
//;--------------------------------------------------------------------------------------------------------
//;Initial Timer1
TMR1 = 0xFF; // Load 0xFF to TMR1 (Initial Timer1 register)
T1CR1 = C_TMR1_Reload | C_TMR1_En; // Enable Timer1, Initial value reloaded from TMR1, Non-stop mode
T1CR2 = C_TMR1_ClkSrc_Inst | C_PS1_Div4; // Enable Prescaler1, Prescaler1 dividing rate = 1:4, Timer1 clock source is instruction clock
//;Setting Interrupt Enable Register
INTE = C_INT_WDT | C_INT_TMR1 | C_INT_TMR0; //
//;Initial Power control register
PCON = C_WDT_En | C_LVR_En; // Enable WDT , Enable LVR
//;Enable Timer0 & Global interrupt bit
PCON1 = C_TMR0_En; // Enable Timer0
ENI(); // Enable all unmasked interrupts
while(1);
}
你没调用延时啊
延时函数
你在需要延时的地方调用
【以下回答由 GPT 生成】
问题分析： 根据给出的代码，可以看出使用了Timer1来实现定时器功能，并在其中插入了中断函数isr()来处理定时器中断。但是循环延时的函数delay()并没有在代码中使用，并且没有调用delay()函数来实现延时一秒的功能。因此，可以在main()函数中添加对delay()函数的调用来实现定时器延迟一秒的功能。
解决方案： 在main()函数中添加对delay()函数的调用来实现定时器延迟一秒的功能。
修改后的代码如下：
void main(void)
{
unsigned char R_shift_regl = 0xFF;
//Initial GPIO
IOSTB = C_PB5_Input | C_PB4_Input | C_PB3_Input; // Set PB0 & PB1 to input mode,others set to output mode
PORTB = 0x07; // PB0、PB1 & PB2 are output High
DISI();
//Initial Timer0
PCON1 = C_TMR0_Dis; // Disable Timer0
TMR0 = 0; // Load 0x00 to TMR0 (Initial Timer0 register)
T0MD = C_PS0_TMR0 | C_PS0_Div8 ; // Prescaler0 is assigned to Timer0, Prescaler0 dividing rate = 1:8, clock source is instruction clock
//Initial WDT (if WDT needs prescaler0 dividing rate )
// T0MD = C_PS0_WDT // Prescaler0 is assigned to WDT, Prescaler0 dividing rate = 1:2 (WDT select interrupt)
//--------------------------------------------------------------------------------------------------------
//Initial Timer1
TMR1 = 0xFF; // Load 0xFF to TMR1 (Initial Timer1 register)
T1CR1 = C_TMR1_Reload | C_TMR1_En; // Enable Timer1, Initial value reloaded from TMR1, Non-stop mode
T1CR2 = C_TMR1_ClkSrc_Inst | C_PS1_Div4; // Enable Prescaler1, Prescaler1 dividing rate = 1:4, Timer1 clock source is instruction clock
//Setting Interrupt Enable Register
INTE = C_INT_WDT | C_INT_TMR1 | C_INT_TMR0; //
//Initial Power control register
PCON = C_WDT_En | C_LVR_En; // Enable WDT , Enable LVR
//Enable Timer0 & Global interrupt bit
PCON1 = C_TMR0_En; // Enable Timer0
ENI(); // Enable all unmasked interrupts
delay(); // 添加延时函数的调用，延时一秒
while(1);
}
这样修改后的代码就可以实现使用定时器延迟一秒的功能了。
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