制作增益为 1 的加法器，实现 C=A+B。
（2）信号 A 和 B 均为正弦波，fA =50kHz，fB =100kHz。要求装置能正确分
离出信号 A’和 B’，且峰峰值均不小于 1V。
（3）信号 A 和 B 均为正弦波，频率分别为 10kHz 的整数倍。要求装置能正
确分离出信号 A’和 B’，且峰峰值均不小于 1V。
该回答通过自己思路及引用到GPTᴼᴾᴱᴺᴬᴵ搜索,得到内容具体如下：以下是用文字描述的电路图和示意图。
1、 增益为1的加法器电路：
增益为1的加法器采用反相输入的运算放大器实现。电路图如下所示：
+---------------------------+
+---| Inverting input (V1-) |
| | |
| | +------+ |
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V1 ---+---|+ / \ | |
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| | +------+ |
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| | +------+ |
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| | / \ | |
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| | +------+ |
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| +-----------+---------------+
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+---------------+
Output (Vout)
2、 分离50kHz和100kHz信号的电路：
为了分离出信号A'和B'，可以使用带通滤波器对输入信号进行滤波，以分离出目标信号。这里采用双二阶有源滤波器电路，分别选择50kHz附近的频率范围来分离信号A'，选择100kHz附近的频率范围来分离信号B'。电路图如下所示：
V1+
|
R1
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+----------+-+
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| C1
| |
| +-------------------+
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| +------+ |
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| / \ | |
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| +------+ |
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| +------+ |
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| / \ | |
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| +------+ |
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| C2 U1
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| +-------------------+
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| +------+ |
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| +------+ |
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| +------+ |
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+---------------------------------+
Vout1 (A')
V1+
|
R2
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+----------+-+
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| C3
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| +-------------------+
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| +------+ |
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| +------+ |
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| +------+ |
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| +------+ |
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| / \ | |
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| +------+ |
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+---------------------------------+
Vout2 (B')
3、 分离10kHz整数倍信号的电路：
为了分离出10kHz整数倍的信号，可以使用带阻滤波器抑制非目标频率范围内的信号。这里采用单二阶有源带阻滤波器电路，以10kHz为中心频率，阻带宽度为2kHz，通过调整Q值可以得到不同的滤波特性。电路图如下所示：
V1+
|
R1
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+-------------+-+
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| C1
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| +---------------------+
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| / \ |
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| +---------------------+
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+---------------------------------------+
Vout (10kHz倍频信号)
以上是手绘的电路图和示意图的文字描述，希望能够帮助您更好地理解这些电路的实现原理。需要注意的是，这些电路图仅供参考，具体的电路设计和实现需要根据具体的应用场景和要求进行选择和调整。
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