mysqli_fetch_array只返回一个结果

I'm trying to make a very, very simple query of a small mysql database, using the following code (with appropriate values in $host, etc.):

$connection = mysqli_connect($host, $user_name, $password, $database);
if (mysqli_connect_errno($connection)) {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($connection, "select university from universities_alpha");
$row = mysqli_fetch_array($result);

echo print_r($result);
echo '<br><br>';
echo print_r($row);

mysqli_close($connection);

As you can see, I printed out the results in a human-readable way, yielding:

mysqli_result Object ( [current_field] => 0 [field_count] => 1 [lengths] => Array ( [0] => 19 ) [num_rows] => 9 [type] => 0 ) 1

Array ( [0] => Arizona State Univ. [university] => Arizona State Univ. ) 1

There are a few example universities in that column, so I'm not sure what I'm doing wrong.

mysqli_fetch_array works by pointers each time it's called

Imagine the following

$result = mysqli_query($connection, "select university from universities_alpha");
$row = mysqli_fetch_array($result); // this is the first row
$row = mysqli_fetch_array($result); // now it's the second row
$row = mysqli_fetch_array($result); // third row

To actually display the data the way you want it to, I suggest you do the following

$rows = array();
$result = mysqli_query($connection, "select university from universities_alpha");
while($row = mysqli_fetch_array($result)) {
    $rows[] = $row;
}

print_r($rows);