Lets say I have the phrase: "Men improve with the years" then if I provide a string that matches "Men improve" I want to get the rest only "with the years". Is this possible with regex?
If you really want to use regex as the questioned asked, here is some code to get you started.
<?php
$str = "Men improve with the years";
$regex = "/Men improve/";
echo preg_replace($regex, "", $str);
?>
Can you try this,
trim(str_replace("Men improve", "","Men improve with the years"));
//OP - with the years
To achieve this type of task we will have many ways, finally we need to choose one of the method which will be suitable for our requirement, this is one my approach
$str = "Men improve with the years";
$substr = "Men improve ";
$result = substr($str, strlen($substr), strlen($str) - 1);
echo trim($result);
If you want to replace $needle at the start of $haystack using preg_replace:
$needle = "Men improve";
$haystack = "Men improve with the years";
echo preg_replace('/^'.preg_quote($needle).'\s*/i', "", $haystack);
/ is the delimiter^ caret matches the position before the first character in the string$needle\s is a shorthand for any kind of white-space, * any amount ofi the ignoreCase modifier after the ending delimiter makes the pattern match case-insensitiveTo match it only, if there is a word boundary after $needle modify the pattern to:
'/^'.preg_quote($needle).'\b\s*/i'