I'd like to be able to select a file by just giving it's name (without extension). For example, I might have a variable $id holding 12. I want to be able to select a file called the-id-in-the-variable, say, 12.png from a directory, but it may have any one of a number of file extensions, listed below:
There is only one occurrence of each ID. I could use a loop and file_exists(), but is there a better way?
Thanks,
James
$matches = glob("12.*");
would return an array with all the matching filenames in the current directory. glob() works much the same as wildcard matching at the shell prompt.
Take a look at glob. Unfortunately, the exact semantics of the $pattern parameter is not described in the manual. But it seems your problem can be solved using this function.
Quick question to OP here:
What is the file extension of this file: somefile.tar.gz? Is it .gz or .tar.gz? :) I ask because most would answer this question as .tar.gz...