说明 table 是 None 啊,也就是没有爬到这个元素
你通过soup.find来查找元素的,对于鲁棒的程序来说,你的需要判定你找到了么?找不到改怎么做,你没做这一步处理哈
import requests
from bs4 import BeautifulSoup
import re
import traceback
def getHTMLText(url,code='utf-8'):
try:
r = requests.get(url)
r.raise_for_status()
r.encoding = code
return r.text
except:
return ""
def getStockList(lst,stockURL):
html = getHTMLText(stockURL,'GB2312')
soup = BeautifulSoup(html,'html.parser')
a = soup.find_all('a')
for i in a:
try:
href = i.attrs['href']
lst.append(re.findall(r"[s][hz]\d{6}",href)[0])
except:
continue
def getStockInfo(lst,stockURL,fpath):
count = 0
for stock in lst:
url = stockURL + stock + ".html"
html = getHTMLText(url)
try:
if html == "":
continue
infoDict = {}
soup = BeautifulSoup(html,'html.parser')
stockInfo = soup.find('div',attrs={'class':'stock-bets'})
name = stockInfo.find_all(attrs={'class':'bets-name'})[0]
infoDict.update({'股票名称': name.text.split()[0]})
keyList = stockInfo.find_all('dt')
valueList = stockInfo.find_all('dd')
for i in range(len(keyList)):
key = keyList[i].text
val = valueList[i].text
infoDict[key] = val
with open(fpath,'a',encoding='utf-8') as f:
f.write(str(infoDict) + '\n')
count = count + 1
print("\r当前进度:{:.2f}%".format(count * 100 / len(lst)),end="")
except:
count = count + 1
print("\r当前进度:{:.2f}%".format(count * 100 / len(lst)), end="")
traceback.print_exc()
continue
def main():
stock_list_url = 'http://quote.eastmoney.com/stocklist.html'
stock_info_url = 'https://gupiao.baidu.com/stock/'
output_file = 'D://BaiduStockInfo.txt'
slist = []
getStockList(slist,stock_list_url)
getStockInfo(slist,stock_info_url,output_file)
main()
错误提示分析:属性错误,'NoneType' 对象没有属性 'find_all' 。这种类型的错误在以前的博客中已经和大家介绍过两个,同样现在这个错误提示依然和以前一样。
错误提示出现的原因:因为上一行代码:stockInfo = soup.find('div', attrs={'class' : 'stock-bets'}) 中获取的数据类型中有空类型'NoneType’ ,通过 print(type(stockInfo)) 可以输出变量stockInfo的类型,发现输出了<class 'bs4.element.Tag'>和<class 'NoneType'>这两种类型。所以出现错误提示的原因是<class 'NoneType'>