我怎样才能传递一个变量

I am having problem with this line of code

$db->select($tbl, plan_name,NULL,'plan_name ="{$pname}"'); 

see my dump of the function

SELECT plan_name FROM plans WHERE plan_name ="{$pname}"

The variable $pname is passed as literal.

Single-quote literals don't get variables replaced inside them.

For reference: http://www.php.net/manual/en/language.types.string.php