给定日期，如何获取日期的年月日

    var start_date;
    var end_date;
console.log("生效时间"+start_date+"失效时间"+end_date)
        var start_year = new Date(start_date).getFullYear;
        var start_month =new Date(start_date).getMonth;
        var start_day = new Date(start_date).getDate;
        var end_year = new Date(end_date).getFullYear;
        var end_month =new Date(end_date).getMonth;
        var end_day = new Date(end_date).getDate;
        console.log("1.年月日"+start_year+start_month+start_day+"2.年月日"+end_year+end_month+end_day)

控制台输出结果如下

生效时间2023-05-01 00:00:00.0失效时间2023-05-06 00:00:00.0
1.年月日function getFullYear() { [native code] }function getMonth() { [native code] }function getDate() { [native code] }2.年月日function getFullYear() { [native code] }function getMonth() { [native code] }function getDate() { [native code] }

我试了var start_year = new start_date.getFullYear;这么写，输出结果是undefind。
我想知道，在给了时间的情况下，怎么获得他的年月日？

var start_date = new Date('2023-05-01');
var end_date = new Date('2023-05-06');

console.log("生效时间"+start_date+"失效时间"+end_date);

var start_year = start_date.getFullYear();
var start_month = start_date.getMonth() + 1;
var start_day = start_date.getDate();
var end_year = end_date.getFullYear();
var end_month = end_date.getMonth() + 1;
var end_day = end_date.getDate();

console.log("1.年月日"+start_year+"-"+start_month+"-"+start_day+" 2.年月日"+end_year+"-"+end_month+"-"+end_day);

你这个调用函数后面的调用函数不对啊，比如说getFullYear，需要使用getFullYear(),这种带有括号的
修改之后你试一下：

var start_date = new Date('2023-05-01 00:00:00.0');
var end_date = new Date('2023-05-06 00:00:00.0');
console.log("生效时间"+start_date+"失效时间"+end_date)
        var start_year = new Date(start_date).getFullYear();
        var start_month =new Date(start_date).getMonth();
        var start_day = new Date(start_date).getDate();
        var end_year = new Date(end_date).getFullYear();
        var end_month =new Date(end_date).getMonth();
        var end_day = new Date(end_date).getDate();
        console.log("1.年月日"+start_year+start_month+start_day+"2.年月日"+end_year+end_month+end_day)