关于#unity#的问题，如何解决？

利用字符数组编写程序来统计字符串“look,if you had one shot,one opportunity,to seize everything you ever wanted."的单词总个数和单词的平均字符数

#include <stdio.h>
#include <string.h>
int main()
{
    char str[] = "look,if you had one shot,one opportunity,to seize everything you ever wanted.";
    int len = strlen(str);
    int word_count = 0;
    int char_count = 0;
    int i;
    for (i = 0; i < len; i++) {
        if (str[i] == ' ' || str[i] == ',' || str[i] == '.') {
            if (char_count > 0) {
                word_count++;
                char_count = 0;
            }
        } else {
            char_count++;
        }
    }
    if (char_count > 0) {
        word_count++;
    }
    printf("单词总个数：%d\n", word_count);
    printf("单词的平均字符数：%.2f\n", (float) len / word_count);
    return 0;
}