I have a string like this:
$sContent = "t('Dashboard').' '.t('Settings Test').' '.t('My Test').' '.t('Other test')";
What I need is a regular expression that get each separate t('') values like:
t('Dashboard')
t('Settings Test')
...
In PHP I used:
$sRegExp = '/t\((.*)\)/i';
preg_match_all($sRegExp, $sContent, $aResults);
I get the same result with main string:
t('Dashboard').' '.t('Settings Test').' '.t('My Test').' '.t('Other test')
You can use:
$sRegExp = '/t\((.*?)\)/
or
$sRegExp = '/t\(([^\)]*)\)/
I'd try with explode function:
$sContent = "t('Dashboard').' '.t('Settings Test').' '.t('My Test').' '.t('Other test')";
$sContents = explode(".' '.", $sContent);
Well, let's assume that you never won't use ' inside that text. Then this should help.
preg_match_all('/t\(\'(?<=t\(\')([^\']*(?!=\'\)))\'\)/', $subject, $result, PREG_PATTERN_ORDER);
$result = $result[0];
Ok, if you want to use ' symbol, you must escape it with \, then try to use the following pattern
/t\(\'(?<=t\(\')(((?=\\\\)\\\\\'|[^\'])*(?!=\'\)))\'\)/