I have an array like that contain key with same name but with number at the end
array example:
Array
(
[field_name0] => name
[field_name1] => sku_package_height
[field_name2] => sku_package_width
[custom_field] => 13
[attribute] => 'test'
[field_name3] => sku_package_length
[field_name4] => sku_package_weight
)
from the example above i want to count how many record that has array key that contain field_name
, so the result I want will be 5
You can do it like below:-
<?php
$original_array = Array
(
'field_name0' => 'name',
'field_name1' => 'sku_package_height',
'field_name2' => 'sku_package_width',
'custom_field' => 13,
'attribute' => 'test',
'field_name3' => 'sku_package_length',
'field_name4' => 'sku_package_weight'
);
$search = "field_name";
$counter = 0;
foreach($original_array as $key=> $value){
if(strstr($key,$search)){
$counter = $counter+1;
}
}
echo $counter;
Output:-https://eval.in/704506
Or
<?php
$original_array = Array
(
'field_name0' => 'name',
'field_name1' => 'sku_package_height',
'field_name2' => 'sku_package_width',
'custom_field' => 13,
'attribute' => 'test',
'field_name3' => 'sku_package_length',
'field_name4' => 'sku_package_weight',
);
$search = "field_name";
$counter = 0;
foreach($original_array as $key=> $value){
if(is_numeric(strpos($key,$search))){
$counter = $counter+1;
}
}
echo $counter;
Output:-https://eval.in/704518
<?php
$array=array("field_name0"=>"name","field_name1"=>"sku_package_height ","field_name2"=>"sku_package_width","custom_field"=>"13","attribute"=>"test","field_name3"=>"sku_package_length", "field_name4"=>"sku_package_weight");
echo $arraykey= count(preg_grep("/^field_name(\d)+$/",array_keys($array)));
?>
you can do this :
$count = 0;
foreach($array as $key => $value){
if(strpos($key,"field_name") > -1){
$count++;
}
}
$count
will have number of keys.
Check the isnumeric of the string position "field_name" in key
$i= 0;
foreach($arrayfields as $keys => $values){
if (is_numeric(strpos($keys,"field_name"))){
$i++;
}
}
echo $i;