PHP正则表达式用括号括起字符串之前的数字

Trying to grab the numbers in front of (h), (w) and (d). These are dynamic and I can't get the syntax for it:

    <ul>
      <li>Make: Mymake</li>
      <li>Model: R-22GTF</li>
      <li>Dimensions: 13.25&#34; (h) x 20.13&#34; (w) x 18.5&#34; (d)</li>
      <li>Sold Individually </li>
      <li>Weight: 0 lbs.</li>
    </ul>

if (preg_match("/Dimensions: ((?:\d+)(?:\.\d*)?)/", $desc, $DIMS) == true)
    { echo $DIMS[1];}

The above only returns 13.25. I would like each in its own array or own variable. Each as defined by the number before (h), the number before (w), and the number before (d).

<?php

$input = "    
     <ul>
      <li>Make: Mymake</li>
      <li>Model: R-22GTF</li>
      <li>Dimensions: 13.25&#34; (h) x 20.13&#34; (w) x 18.5&#34; (d)</li>
      <li>Sold Individually </li>
      <li>Weight: 0 lbs.</li>
    </ul>";

$re = '/.* (\d+\.\d+).*\(h\) .* (\d+\.\d+).*\(w\) .* (\d+\.\d+).*\(d\)/';
if(preg_match($re, $input, $matches))
   echo sprintf("H: %s   W: %s   D: %s
", $matches[1], $matches[2], $matches[3]);
?>

Try the regex bellow, hope i understood well what you are trying to extract :)

[\d.]+(?=&)

EDIT:

global regex

/[\d.]+(?=&)/g

ALso if you want to test various combinations of regexes, please try some live online regex validators like:

http://gskinner.com/RegExr/

It will match your expressions as you type them.

You should be able to do a print_r($DIMS) on this

Dimensions:[^\d.;(<]*([\d.]*)[^;(<]*;[^(<]*\(h\)[^\d.;(<]*([\d.]*)[^;(<]*;[^(<]*\(w\) [^\d.;(<]*([\d.]*)[^;(<]*;[^(<]*\(d\)

expanded

Dimensions: 
   [^\d.;(<]* ([\d.]*) [^;(<]* ; [^(<]* \(h\)
   [^\d.;(<]* ([\d.]*) [^;(<]* ; [^(<]* \(w\)
   [^\d.;(<]* ([\d.]*) [^;(<]* ; [^(<]* \(d\)

Its a little strict on validation, but its greedy, so redundant overflow restrictions are necessary. You can just replace the negative classes with .*? if you want.