使一个数组被n整除？

I have an array:

$arr = ['a', 'b', 'c', 'd', 'e', 'f', 'g'];

Is there a way to make it contain elements only divisible by 3 (or n)? So in the above example g would be removed as it's left over from a division of 3?

EDIT

I want amount of elements divisible by 3.

You can use a combination of array_slice(), count() and modulus (%) to get the array evenly divisible:

$arr_length = count($arr);
$new_arr = array_slice($arr, 0, $arr_length - ($arr_length % 3));

@panthro simply try with for loop like below and use array_pop()

<?php
    $arr = ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
    if(count($arr) % 3 != 0){
        $remainder = count($arr) % 3;
        for($i=0;$i < $remainder;$i++){
            array_pop($arr);
        }
    }
    echo "<pre>";
    print_r($arr); //final array divisible by 3

Sounds like you want the length to be divisible by 3 and you want to remove elements until that happens. array_slice can help you out here.

$to_remove = count($arr) % 3;
if($to_remove > 0){
    $arr = array_slice($arr, 0, -$to_remove);
}