Probably a dumb question but is there a more clever way of checking that an image 1360x455 is within the allowed tolerance of say +-10 of two other numbers I have defined? :
<?php
$w = 1360;
$h = 455;
$cw = 1360;
$ch = 460;
$tol = 10; //px
if ((int) $w >= (int) ($cw-$tol) && (int) $w <= (int) ($cw+$tol) &&
(int) $h >= (int) ($ch-$tol) && (int) $h <= (int) ($ch+$tol)) {
echo "you are within the tolerance {$cw}x{$ch}px by +-{$tol} px.";
};
So I basically just want to make sure the user doesn't go outside of these bounds when uploading. The above code works, just wondering if I could be more clever about it. The method already knows these values as they are passed in.
A more concise method would be to subtract the input value against the reference and ensure the absolute value (abs()) of the result is less than or equal to your tolerance.
The difference between the reference value an input value must be within 10, and subtracting them will produce a positive or negative integer. Using abs() strips its sign, so it's a simple <= comparison with the tolerance value.
$w = 1360;
$h = 455;
$cw = 1360;
$ch = 460;
$tol = 10; //px
if (abs($cw - $w) <= $tol && abs($ch - $h) <= $tol) {
echo "you are within the tolerance {$cw}x{$ch}px by +-{$tol} px.";
}
The casting with (int) is generally unnecessary here. But if your function may be receiving string values, I would suggest casting the variables to ints before the calculation just so to reduce clutter.