关于#编译器#的问题，如何解决？


float tri_center_alpha;
float tri_center_beta;
float tri_center_sec1_alpha[4] = {5.0/24*Udc,5/24*Udc,1.0/2*Udc,1.0/2*Udc};
float tri_center_sec1_beta[4] = {1.7320508076/24*Udc,-1.7320508076/24*Udc,1.7320508076/18*Udc,-1.7320508076/18*Udc};
float tri_center_sec2_alpha[4] = {1.0/12*Udc,5.0/24*Udc,1.0/6*Udc,1.0/3*Udc};
float tri_center_sec2_beta[4] = {1.7320508076/6*Udc,3.0*1.7320508076/24*Udc,5.0*1.7320508076/18*Udc,(3.0+2.0*1.7320508076)/18*Udc};
float tri_center_sec3_alpha[4] = {5.0/24*Udc,-1.0/12*Udc,-1.0/3*Udc,-1.0/6*Udc};
float tri_center_sec3_beta[4] = {3.0*1.7320508076/24*Udc,1.7320508076/6*Udc,(3.0+2*1.7320508076)/18*Udc,5.0*1.7320508076/18*Udc};
float tri_center_sec4_alpha[4] = {5.0/24*Udc,-5.0/24*Udc,-1.0/2*Udc,-1.0/2*Udc};
float tri_center_sec4_beta[4] = {1.7320508076/24*Udc,1.7320508076/24*Udc,-1.7320508076/18*Udc,1.7320508076/18*Udc};
float tri_center_sec5_alpha[4] = {1.0/12*Udc,-5.0/24*Udc,-1.0/6*Udc,-1.0/3*Udc};
float tri_center_sec5_beta[4] = {1.7320508076/6*Udc,-3.0*1.7320508076/24*Udc,-5.0*1.7320508076/18*Udc, -(3.0+2.0*1.7320508076)/18*Udc};
float tri_center_sec6_alpha[4] = {5.0/24*Udc,1.0/12*Udc,1.0/3*Udc,1.0/6*Udc};
float tri_center_sec6_beta[4] = {3.0*1.7320508076/24*Udc,-1.7320508076/6*Udc,-(3.0+2.0*1.7320508076)/18*Udc,-5.0*1.7320508076/18*Udc};

switch(N)
           {
               case 1:
                   tri_center_alpha = tri_center_sec1_alpha[4];
                   tri_center_beta = tri_center_sec1_beta[4];
                   break;
               case 2:
                   tri_center_alpha = tri_center_sec2_alpha[4];
                   tri_center_beta = tri_center_sec2_beta[4];
                   break;
               case 3:
                   tri_center_alpha = tri_center_sec3_alpha[4];
                   tri_center_beta = tri_center_sec3_beta[4];
                   break;
               case 4:
                   tri_center_alpha = tri_center_sec4_alpha[4];
                   tri_center_beta = tri_center_sec4_beta[4];
                   break;
               case 5:
                   tri_center_alpha = tri_center_sec5_alpha[4];
                   tri_center_beta = tri_center_sec5_beta[4];
                   break;
               default:
                   tri_center_alpha = tri_center_sec4_alpha[4];
                   tri_center_beta = tri_center_sec4_beta[4];
                   break;
           }

代码如图所示，从case1:tri_center_alpha = tri_center_sec1_alpha[4]开始，每一行编译器都警告#177-D subscript out of range,请问该如何解决，是我把代码写的太复杂了吗，有没有简单一点的写法？

基于Monster 组和GPT的调写：
数组的索引应该是0-3而不是4
尝试访问索引为4的元素时，编译器会提示数组下标超出范围。

为了解决这个问题，要将数组的索引更正为从0开始，例如：

tri_center_alpha = tri_center_sec1_alpha[0];
tri_center_beta = tri_center_sec1_beta[0];

数组下标越界， 下标从0开始， 所以4个元素只能到3

switch(N)
{
    case 1:
        tri_center_alpha = tri_center_sec1_alpha[3];
        tri_center_beta = tri_center_sec1_beta[3];
        break;
    case 2:
        tri_center_alpha = tri_center_sec2_alpha[3];
        tri_center_beta = tri_center_sec2_beta[3];
        break;
    case 3:
        tri_center_alpha = tri_center_sec3_alpha[3];
        tri_center_beta = tri_center_sec3_beta[3];
        break;
    case 4:
        tri_center_alpha = tri_center_sec4_alpha[3];
        tri_center_beta = tri_center_sec4_beta[3];
        break;
    case 5:
        tri_center_alpha = tri_center_sec5_alpha[3];
        tri_center_beta = tri_center_sec5_beta[3];
        break;
    default:
        tri_center_alpha = tri_center_sec4_alpha[3];
        tri_center_beta = tri_center_sec4_beta[3];
        break;
}

改成这样试试