编写一个程序，将一个数组内的偶数打印出来

编写一个程序，求出整型数组a中偶数元素个数，并将其结果打印出来。数组为：
int a[6] = (8, 7,12,9,16,18)；

望给个采纳，谢谢！
1、效果如下

#include<iostream>
using namespace std;
int main() {
    int count = 0;
    int a[6] = { 8, 7, 12, 9, 16, 18 };
    for (int i = 0; i < 6; i++)
    {
        if (a[i] % 2 == 0) {
            count += 1;
            printf("%d\n", a[i]);
        }
    }
    printf("偶数元素个数：%d\n", count);
    
    system("\npause");
    return 0;
}

#include <stdio.h>
 
int main()
{
    int a[6] = {8, 7, 12, 9, 16, 18};
    int count = 0;
 
    for (int i = 0; i < 6; i++)
    {
        if (a[i] %2== 0)
        {
            count++;
        }
    }
 
    printf("偶数元素个数为：%d\n", count);
 
    return 0;
}

    int a[6] = {8, 7, 12, 9, 16, 18};
    int index = 0;
    int count = 0;
    int sz = sizeof(a) / sizeof(a[0]);
    while (true) {
        if (a[index] % 2 == 0) {
            count+=1;
        }
        if (index >= sz - 1) {
            break;
        }
        index++;
    }

    printf("%d",count);

写得都不出错，我的也是一种写法

遍历循环，除以2来判断偶数，满意请采纳，

#include <stdio.h>
 
int main()
{
    int a[6] = {8, 7, 12, 9, 16, 18};
    int count = 0;
 
    for (int i = 0; i < 6; i++)
    {
        if (a[i] %! (MISSING)== 0)
        {
            count++;
        }
    }
 
    printf("The number of even elements in the array is %!d(MISSING)\n", count);
 
    return 0;
}

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