如何在arr数组中找到与arr_1相同的对象
如何在arr数组中找到与arr_1相同的对象
let arr = [{
"id": 41,
"name": "详情一",
"details": [{
"index": 1,
"name": "皮皮",
"age": 32,
"address": '南京市'
}, {
"index": 1,
"name": "悠悠",
"age": 33,
"address": '琼海市'
}, {
"index": 2,
"name": "涛涛",
"age": 23,
"address": '杭州市'
}, {
"index": 1,
"name": "赵三",
"age": 42,
"address": '琼海市'
}, {
"index": 1,
"name": "八八",
"age": 21,
"address": '北京市'
}]
}, {
"id": 43,
"name": "详情二",
"details": [{
"index": 1,
"name": "张三",
"age": 12,
"address": '上海市'
}, {
"index": 1,
"name": "李四",
"age": 33,
"address": '杭州市'
}, {
"index": 1,
"name": "王五",
"age": 21,
"address": '南昌市'
}, {
"index": 1,
"name": "赵六",
"age": 32,
"address": '南京市'
}]
}]
let arr_1 = [{
"index": 1,
"name": "张三",
"age": 12,
"address": '上海市浦东新区'
}, {
"index": 1,
"name": "李四",
"age": 33,
"address": '杭州市'
}, {
"index": 1,
"name": "王五",
"age": 21,
"address": '南昌市'
}, {
"index": 1,
"name": "赵六",
"age": 32,
"address": '南京市'
}]
不知道具体是要实现什么效果，下面是将arr_1中项在arr 第几项和details中位置打印出来
<script>
let arr = [{
"id": 41,
"name": "详情一",
"details": [{
"index": 1,
"name": "皮皮",
"age": 32,
"address": '南京市'
}, {
"index": 1,
"name": "悠悠",
"age": 33,
"address": '琼海市'
}, {
"index": 2,
"name": "涛涛",
"age": 23,
"address": '杭州市'
}, {
"index": 1,
"name": "赵三",
"age": 42,
"address": '琼海市'
}, {
"index": 1,
"name": "八八",
"age": 21,
"address": '北京市'
}]
}, {
"id": 43,
"name": "详情二",
"details": [{
"index": 1,
"name": "张三",
"age": 12,
"address": '上海市'
}, {
"index": 1,
"name": "李四",
"age": 33,
"address": '杭州市'
}, {
"index": 1,
"name": "王五",
"age": 21,
"address": '南昌市'
}, {
"index": 1,
"name": "赵六",
"age": 32,
"address": '南京市'
}]
}]
let arr_1 = [{
"index": 1,
"name": "张三",
"age": 12,
"address": '上海市浦东新区'
}, {
"index": 1,
"name": "李四",
"age": 33,
"address": '杭州市'
}, {
"index": 1,
"name": "王五",
"age": 21,
"address": '南昌市'
}, {
"index": 1,
"name": "赵六",
"age": 32,
"address": '南京市'
}]
let result = [];
arr_1.forEach((i, iIndex) => {
arr.forEach((j, jIndex) => {
var index = j.details.findIndex(k => k.name == i.name && k.age == i.age && k.address == i.address);//根据name，age，address一样判断为同一个人
if (index != -1) {
result.push(`arr_1第${iIndex + 1}项${i.name}出现在arr第${jIndex + 1}项的details数组第${index + 1}项中`)
}
})
});
console.log(result)
</script>
该回答引用GPTᴼᴾᴱᴺᴬᴵ
可以使用循环遍历arr数组，再对比每个元素的details数组是否包含arr_1数组中的所有对象，如果包含就返回该元素，否则返回null。示例代码如下：
function findArr(arr, arr_1) {
for (let i = 0; i < arr.length; i++) {
let details = arr[i].details;
let found = arr_1.every(obj => {
return details.some(detail => {
return detail.name === obj.name && detail.age === obj.age && detail.address === obj.address;
});
});
if (found) {
return arr[i];
}
}
return null;
}
let result = findArr(arr, arr_1);
console.log(result);
该函数会返回包含arr_1数组中所有对象的元素，如果没有匹配的元素则返回null。
以下答案引用自GPT-3大模型,请合理使用：
示例
//使用forEach方法可以循环arr_1,来查找在arr中是否存在与之相同的对象
let newArr = [];
arr_1.forEach(item => {
//标记arr_1中遍历到的当前对象是否存在arr中
let isExisted = false;
//查找arr中是否有与之相同的对象
arr.forEach(item_1 => {
item_1.details.forEach(item_2 => {
//如果当前item和item_2完全一致，说明存在与之相同的对象
if (JSON.stringify(item_2) === JSON.stringify(item)) {
newArr.push(item_2);
isExisted = true;
}
})
});
// 如果数组arr中不存在相同的对象，那么就压入arr_1中遍历到的当前对象
if (!isExisted) {
newArr.push(item)
}
});
console.log(newArr);
如果我的回答解决了您的问题，请采纳我的回答
1、以下为人工手写亲测有效（望给个采纳，谢谢！）
<script type="text/javascript">
let arr = [{
"id": 41,
"name": "详情一",
"details": [{
"index": 1,
"name": "皮皮",
"age": 32,
"address": '南京市'
}, {
"index": 1,
"name": "悠悠",
"age": 33,
"address": '琼海市'
}, {
"index": 2,
"name": "涛涛",
"age": 23,
"address": '杭州市'
}, {
"index": 1,
"name": "赵三",
"age": 42,
"address": '琼海市'
}, {
"index": 1,
"name": "八八",
"age": 21,
"address": '北京市'
}]
}, {
"id": 43,
"name": "详情二",
"details": [{
"index": 1,
"name": "张三",
"age": 12,
"address": '上海市'
}, {
"index": 1,
"name": "李四",
"age": 33,
"address": '杭州市'
}, {
"index": 1,
"name": "王五",
"age": 21,
"address": '南昌市'
}, {
"index": 1,
"name": "赵六",
"age": 32,
"address": '南京市'
}]
}]
let arr_1 = [{
"index": 1,
"name": "张三",
"age": 12,
"address": '上海市浦东新区'
}, {
"index": 1,
"name": "李四",
"age": 33,
"address": '杭州市'
}, {
"index": 1,
"name": "王五",
"age": 21,
"address": '南昌市'
}, {
"index": 1,
"name": "赵六",
"age": 32,
"address": '南京市'
}]
// 三重循环法
var sameArr = [];
var length = arr.length;
for (var i = 0; i < length; i++) {
var dataDetails = arr[i].details;
var lengthDetails = dataDetails.length;
for (var j = 0; j < lengthDetails; j++) {
var dataOne = dataDetails[j];
for (var l = 0; l < arr_1.length; l++) {
var dataTwo = arr_1[l];
// 只判断name相同，则认为是相同的对象
if (dataOne.name == dataTwo.name) {
sameArr.push(dataOne);
}
}
}
}
console.log(sameArr);
</script>
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