I'm having trouble finding a correct regex to achieve what I want.
I have a sentence like that :
Hi, my name is Stan, you are welcome, hello.
and I would like to transform it like that :
[hi|hello|welcome], my name is [stan|jack] you are [hi|hello|welcome] [hi|hello|welcome].
Right now my regex is half working, because somes words are not replaced, and those replaced are deleting some characters
Here is my test code
<?php
$test = 'Hi, my name is Stan, you are welcome, hello.';
$words = array(
array('hi', 'hello', 'welcome'),
array('stan', 'jack'),
);
$result = $test;
foreach ($words as $group) {
if (count($group) > 0) {
$replacement = '[' . implode('|', $group) . ']';
foreach ($group as $word) {
$result = preg_replace('#([^\[])' . $word . '([^\]])#i', $replacement, $result);
}
}
}
echo $test . '<br />' . $result;
Any help will be appreciated
The regex you are using is overcomplicated. You simply need to use a regex substitution using regular brackets ():
<?php
$test = 'Hi, my name is Stan, you are welcome, hello.';
$words = array(
array('hi', 'hello', 'welcome'),
array('stan', 'jack'),
);
$result = $test;
foreach ($words as $group) {
if (count($group) > 0) {
$imploded = implode('|', $group);
$replacement = "[$imploded]";
$search = "($imploded)";
$result = preg_replace("/$search/i", $replacement, $result);
}
}
echo $test . '<br />' . $result;
preg_replace supports array as parameter. No need to iterate with a loop.
$s = array("/(hi|hello|welcome)/i", "/(stan|jack)/i");
$r = array("[hi|hello|welcome]", "[stan|jack]");
preg_replace($s, $r, $str);
or dynamically
$test = 'Hi, my name is Stan, you are welcome, hello.';
$s = array("hi|hello|welcome", "stan|jack");
$r = array_map(create_function('$a','return "[$a]";'), $s);
$s = array_map(create_function('$a','return "/($a)/i";'), $s);
echo preg_replace($s, $r, $str);
//[hi|hello|welcome], my name is [stan|jack], you are [hi|hello|welcome], [hi|hello|welcome].
Your regular expression:
'#([^\[])' . $word . '([^\]])#i'
matches one character before and after $word
as well. And as they do, they replace it. So your replacement string needs to reference these parts, too:
'$1' . $replacement . '$2'