如何批量替换各种容器中字符串中的某个字母或汉字,比如,我想一次性把c替换成x,e替换成y,然后再打印容器。下面有四种容器,请分容器类型解答,例如元组就先转成列表再转回元组。
示例容器如下:(手机打的,如果括号标点错了改一下)
A=["a","bcd","acd","cde"]
B=("a","bcd","acd","cde")
C={"a","bcd","acd","cde"}
D={a:"bcd ",b:"acd",c:"cde"}
其他要求:这里示例使用的是英文字母。请保证当它是中文字符、符号时也能顺利使用。
针对四种容器
列表:
A = ["a", "bcd", "acd", "cde"]
for i, val in enumerate(A):
A[i] = val.replace('c', 'x').replace('e', 'y')
print(A)
元组
B = ("a", "bcd", "acd", "cde")
B = list(B)
for i, val in enumerate(B):
B[i] = val.replace('c', 'x').replace('e', 'y')
B = tuple(B)
print(B)
集合
C = {"a", "bcd", "acd", "cde"}
C = {val.replace('c', 'x').replace('e', 'y') for val in C}
print(C)
字典
D = {'a': "bcd", 'b': "acd", 'c': "cde"}
for key in D:
D[key] = D[key].replace('c', 'x').replace('e', 'y')
print(D)
这些代码可以实现批量替换容器中字符串中的某个字母或汉字。