php DateTime转换unix时间戳

A question that I have is why doesn't the DateTime class convert the unix epoc by default Example would be



function convert($date){
$d = new DateTime($date);
echo $d;
}
$now = time();
convert($now);

I mean sure there is 20 different date/time functions in php but one of the most common formats Errors can somebody shed some light on if i am missing something without passing a string time through 2 other functions "messy code" to pass it to the DateTime Class ?

function convert($date){
$d = new DateTime($date);
echo $d;
}
$now = time();
convert('@'.$now);

example #2 http://www.php.net/manual/en/datetime.construct.php

Try looking at this site... It has helped me many times in different languages. http://www.epochconverter.com/

so i think you want this:

function convert($date)
{
    $d = date("r", $date);
    echo $d;
}

$now = time();

convert($now);
echo "<br><br>";
convert("1296928800");
echo "<br><br>";

#  60  * 60   * 24    * 365  * 40
# secs   mins   hours   days   years

convert("1296928800" + (60 * 60 * 24 * 365 * 40));
echo "<br><br>";
convert($now + (60 * 60 * 24 * 365 * 40));

This converts seconds since the Unix Epoch to DateTime:

$my_php_datetime_object =  DateTime::createFromFormat('U', $seconds_epoch)

http://php.net/manual/en/datetime.createfromformat.php