jypter notebook中的.srot为什么未将list中的”苹果“倒序放在最后输出呢

jypter notebook中的.srot为什么未将list中的”苹果“倒序放在最后输出呢?
相关代码:
# 这是我的购物清单
shoplist = ['apple', 'mango', 'carrot', 'banana']

print('I have', len(shoplist), 'items to purchase.')

print('These items are:', end=' ')
for item in shoplist:
    print(item, end=' ')

print('\nI also have to buy rice.')
shoplist.append('rice')
print('My shopping list is now', shoplist)

print('I will sort my list now')
shoplist.sort()
print('Sorted shopping list is', shoplist)

print('The first item I will buy is', shoplist[0])
olditem = shoplist[0]
del shoplist[0]
print('I bought the', olditem)
print('My shopping list is now', shoplist)

结果:

img

麻烦各位解惑,十分感谢!

python sort()函数对字符串排序,默认是按照ASCII字符顺序排序,意味着对字母排序的时候,字母越靠后,值越大。所以升序的话apple在前面

升序,苹果在前面对的啊