C语言计算行舟问题C语言

行舟问题

输入样例
48.6
6:32:24.2 9:37:18.5
12:46:15.3 17:4:19.8
输出样例
13.53
2.24

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#inclue
int main()
{
    double d,t1,t2,t3,t4;
    //
    //
}



#include<stdio.h>
int main() {
    double d;
    int h[4], m[4];
    double s[4];
    double t1, t2;
    double v1, v2;
    scanf("%lf", &d);
    for (int i = 0; i < 4; ++i) {
        scanf("%d:%d:%lf", &h[i], &m[i], &s[i]);
    }
    t1 = (h[1] * 3600 + m[1] * 60 + s[1] - h[0] * 3600 - m[0] * 60 - s[0]) / 3600;
    t2 = (h[3] * 3600 + m[3] * 60 + s[3] - h[2] * 3600 - m[2] * 60 - s[2]) / 3600;
    if (t1 < 0)
        t1 += 24;
    if (t2 < 0)
        t2 += 24;
    v1 = (d / t1 + d / t2) / 2;
    v2 = (d / t1 - d / t2) / 2;
    printf("%.2lf\n%.2lf", v1, v2);
}

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