切换图片，并且更改属性

怎么做，完全没思路。怎么做，完全没思路
怎么做，完全没思路。怎么做，完全没思路

img

参考这个


<!DOCTYPE html>
<html lang="en">

<head>
  <meta charset="UTF-8">
  <meta http-equiv="X-UA-Compatible" content="IE=edge">
  <meta name="viewport" content="width=device-width, initial-scale=1.0">
  <title>Document</title>
  <style>
    #h1 {
      width: 300px;
      height: 200px;
    }

    #image_ul {
      display: flex;
    }

    #image_ul img {
      width: 100px;
      height: 50px;
    }

    .active {
      border: 2px solid red;
    }

    .show_btn {
      border: none;
    }
  </style>
</head>

<body>
  <img id="h1" src="https://img2.baidu.com/it/u=2666428851,2803796192&fm=253&fmt=auto&app=138&f=JPEG?w=889&h=500"
    alt="">
  <div id="image_ul">
    <img id="li1" class="active" onclick="show(this)"
      src="https://img2.baidu.com/it/u=2666428851,2803796192&fm=253&fmt=auto&app=138&f=JPEG?w=889&h=500" alt="">
    <img id="li3" class="show_btn" onclick="show(this)"
      src="https://gimg2.baidu.com/image_search/src=http%3A%2F%2Fi0.hdslb.com%2Fbfs%2Farchive%2F1fcc576d60396a385003543dbab1ac8a9d32f72e.jpg&refer=http%3A%2F%2Fi0.hdslb.com&app=2002&size=f9999,10000&q=a80&n=0&g=0n&fmt=auto?sec=1674715864&t=9822598193f65aabe01fee433814c378"
      alt="">
    <img id="li4" class="show_btn" onclick="show(this)" src="" alt="">
    <img id="li5" class="show_btn" onclick="show(this)" src="" alt="">
  </div>
</body>
<script>

  function show(e) {
    let h1 = document.getElementById("h1"); //获取 h1
    h1.src = e.src; //赋值 h1 点击 图片的 src
    let image_ul = document.getElementById("image_ul");
    let imgs = image_ul.getElementsByTagName("img");
    for (var i = 0; i < imgs.length; i++) {
      if (e.id == imgs[i].id) {
        e.className = "active";
      } else {
        imgs[i].className = "show_btn"
      }
    }

  }
</script>

</html>

<img id="my-image" src="image1.jpg" alt="">

document.getElementById('my-image').src = 'image2.jpg';

<div id="my-element">This is my element</div>

document.getElementById('my-element').style.color = 'red';

望采纳。