This couple of days I've working on this project. i didnt know whats the error of this code and what method should i use to make my code better, my friend told me to apply array but im not familiar on that method i try to research and research in couple of days but it not working. What i need is to make a program that will count level 1,2,3,4 and 5 and display for example how many data(row) got level 5 in jan,feb,mar,apr,may,jun,jul,aug,sep,oct,nov and dec, in this sample code i only show filtering level 5 only because i dont want may reader of this to be confuse. thank you guys :-(
This is My sample table
Table: sample
+-------------+------------------+-----------+
| date | level | id |
+-------------+------------------+-----------+
| 2012-03-01 | 4 | 1 |
| 2012-02-02 | 1 | 2 |
| 2012-04-03 | 4 | 3 |
| 2012-05-14 | 1 | 4 |
| 2010-01-05 | 5 | 5 |
| 2009-01-05 | 2 | 6 |
| 2008-01-05 | 3 | 7 |
| 2012-02-02 | 1 | 8 |
| 2012-06-03 | 4 | 9 |
| 2012-07-14 | 1 | 10 |
| 2010-01-05 | 5 | 11 |
| 2009-01-05 | 2 | 12 |
| 2012-08-05 | 3 | 13 |
+-------------+------------------+-----------+
This query is selecting all data with a year of 2012 and order by date
$query = mysql_query("select * from table where year(date)='2012' order by date");
This while loop generate all the record that $query prefer. In the loop there was the HOPING condition that filter the records with all 5 LEVEL... when the data(produce by $query) is level 5 the $level5 will increment by 1, then that data will under go to another if statement to determined what month the data(produce by $query) belong, let say the data is 2012-05-14, so the data will go in the if statement if(Date_format($ii['date'],'%m'))==05) and increase the $level5_may by 1 and after that...
while($ii=mysql_fetch_array($query))
{
if($ii['level']==5)
{
$level5++;
if(Date_format($ii['date'],'%m'))==1)
{
$level5_jan++;
}elseif(Date_format($ii['date'],'%m'))==02)
{
$level5_feb++;
}elseif(Date_format($ii['date'],'%m'))==03)
{
$level5_mar++;
}elseif(Date_format($ii['date'],'%m'))==04)
{
$level5_apr++;
}elseif(Date_format($ii['date'],'%m'))==05)
{
$level5_may++;
}elseif(Date_format($ii['date'],'%m'))==06)
{
$level5_jun++;
}elseif(Date_format($ii['date'],'%m'))==07)
{
$level5_jul++;
}elseif(Date_format($ii['date'],'%m'))==08)
{
$level5_aug++;
}elseif(Date_format($ii['date'],'%m'))==09)
{
$level5_sep++;
}elseif(Date_format($ii['date'],'%m'))==10)
{
$level5_oct++;
}elseif(Date_format($ii['date'],'%m'))==11)
{
$level5_nov++;
}elseif(Date_format($ii['date'],'%m'))==12)
{
$level5_dec++;
}
}
}
this part of the code will now collect the result of the if statement
echo"
number of 5 stars: $level5 <br>
jan:$level5_jan <br>
feb:$level5_feb <br>
mar:$level5_mar <br>
apr:$level5_apr <br>
may:$level5_may <br>
jun:$level5_jun <br>
jul:$level5_jul <br>
aug:$level5_aug <br>
sep:$level5_sep <br>
oct:$level5_oct <br>
nov:$level5_nov <br>
dec:$level5_dec <br>
";
$date = 'date';
$level = 'level';
$year = '2012';
$result1 = mysql_query("SELECT *, DATE_FORMAT( $date, '%m' ) AS monthz FROM sample WHERE year($date) = '$year' ORDER BY $date");
while($row=mysql_fetch_array($result1))
{
$count++;
if($row['smi_level']=='5star')
{
if($row['monthz']==1)
{
$jan++;
}elseif($row['monthz']==2)
{
$feb++;
}elseif($row['monthz']==3)
{
$mar++;
}elseif($row['monthz']==4)
{
$apr++;
}elseif($row['monthz']==5)
{
$may++;
}elseif($row['monthz']==6)
{
$jun++;
}elseif($row['monthz']==7)
{
$jul++;
}elseif($row['monthz']==8)
{
$aug++;
}elseif($row['monthz']==9)
{
$sep++;
}elseif($row['monthz']==10)
{
$oct++;
}elseif($row['monthz']==11)
{
$nov++;
}elseif($row['monthz']==12)
{
$dec++;
}
}
}
echo" $jan $feb $mar $apr $may $jun $jul $aug $sep $oct $nov $dec";
This is my complete solution about my problem(but im not happy about my solution because the code was bulky or bulk, and I've not use array so i was disappoint o my self) thank to F. Müller for giving me idea about arrays and the use of AS in *, DATE_FORMAT( $date, '%m' ) AS monthz and to Arun Killu Thanks for suggestion. I know my solution code is not quite good, hahaha Im open for any suggestion thanks
select *,count(1) as total from table where year(date)='2012'
group by level order by date
SQL:
"SELECT level, id, date AS UNIX_TIMESTAMP(date) FROM table WHERE year(date) = '2012' ORDER BY date"
PHP:
while($row = mysql_fetch_assoc($query))
{
$levels = array(); // This is where the data for the monthly counting goes in
$currentLevel = $row['level']; // The current level in the loop
$currentDate = date('n', $row['date']); // The current month without leading zeroes
if ($currentLevel === 5) // Check if the current level equals 5
{
$levels[$currentLevel][$currentDate] += 1;
}
}
Should do what you want but it is not tested.
NOTE: It is not recommendet to use multiple query of course (bad performance)
EDIT
SELECT field1, field2, field3, date AS UNIX_TIMESTAMP(date) FROM table WHERE year(date) = '2012' ORDER BY date)
or try this (not sure if this works properly):
SELECT *, date AS UNIX_TIMESTAMP(date) FROM ...
UNIX_TIMESTAP
If your field is typeof timestamp or datetime UNIX_TIMESTAMP(date) will return the date in seconds since November 1971 (see: http://en.wikipedia.org/wiki/Unix_time) and here (see: http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_unix-timestamp)
With unix timestamp it is very easy to handle dates - and you can easily calculate with them and format to whatever you like.