C语言函数指针解决问题

各位有谁知道解答思路么
用题目做给条件进行作答
在线等候解惑
感谢

#include <stdio.h>

int findNum(char *str[], int n, int num[])
{
   int count = 0, i, j, t = 0, f = 0;
   char ch;
   for (i = 0; i < n; i++)
   {
      j = 0;
      ch = str[i][0];
      while (ch)
      {
         if (ch >= '0' && ch <= '9')
         {
            t = t * 10 + ch - '0';
            f = 1;
         }
         if (ch < '0' || ch > '9' || str[i][j + 1] == '\0')
         {
            if (f)
            {
               num[count] = t;
               count++;
               t = 0;
            }

            f = 0;
         }
         j++;
         ch = str[i][j];
      }
   }
   return count;
}

void order(int *a, int start, int end)
{
   int t;
   for (int i = start; i < end - 1; i++)
   {
      for (int j = i + 1; j < end; j++)
      {
         if (a[i] < a[j])
         {
            t = a[i];
            a[i] = a[j];
            a[j] = t;
         }
      }
   }
}

int main()
{

   char *str[3] = {"12df 34*99jji1", "we8967ii*ke3", "45ju7**66"};
   int i, count;
   int num[20] = {1, 2, 3, 4, 5};
   for (i = 0; i < 3; i++)
      puts(str[i]);
   printf("\n");
   count = findNum(str, 3, num);
   order(num, 0, count - 1);
   for (i = 0; i < count; i++)
      printf("%d ", num[i]);

   return 0;
}