题目内容：
无线电台的RS制信号报告是由三两个部分组成的：
R(Readability) 信号可辨度即清晰度.
S(Strength) 信号强度即大小.
其中R位于报告第一位，共分5级，用1—5数字表示.
1---Unreadable
2---Barely readable, occasional words distinguishable
3---Readable with considerable difficulty
4---Readable with practically no difficulty
5---Perfectly readable
报告第二位是S，共分九个级别，用1—9中的一位数字表示
1---Faint signals, barely perceptible
2---Very weak signals
3---Weak signals
4---Fair signals
5---Fairly good signals
6---Good signals
7---Moderately strong signals
8---Strong signals
9---Extremely strong signals
现在，你的程序要读入一个信号报告的数字，然后输出对应的含义。如读到59，则输出：
Extremely strong signals, perfectly readable.
输入格式:
一个整数，信号报告。整数的十位部分表示可辨度，个位部分表示强度。输入的整数范围是[11,59]内有效的数字，这个范围外的数字不可能出现在测试数据中。
输出格式：
一句话，表示这个信号报告的意义。按照题目中的文字，先输出表示强度的文字，跟上逗号和空格，然后是表示可辨度的文字，跟上句号。注意可辨度的句子的第一个字母是小写的。注意这里的标点符号都是英文的。
输入样例：
33
输出样例：
Weak signals, readable with considerable difficulty.
时间限制：500ms内存限制：32000kb
我的代码是：
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// TODO Auto-generated method stub
//初始化
System.out.println("请输入数字：");
Scanner in = new Scanner(System.in);
int S ;
int R ;
int number = in.nextInt();
if(number>=11&&number<=59)
{
R = number/10;
S = number%10;
switch(R) {
case 1:
System.out.print("unreadable");
break;
case 2:
System.out.print("barely readable, occasional words distinguishable");
break;
case 3:
System.out.print("readable with considerable difficulty");
break;
case 4:
System.out.print("readable with practically no difficulty");
break;
case 5:
System.out.print("perfectly readable");
break;
}
System.out.print(",");
switch(S) {
case 1:
System.out.print("Faint signals, barely perceptible");
break;
case 2:
System.out.print("Very weak signals");
break;
case 3:
System.out.print("Weak signals");
break;
case 4:
System.out.print("Fair signals");
break;
case 5:
System.out.print("Fairly good signals");
break;
case 6:
System.out.print("Good signals");
break;
case 7:
System.out.print("Moderately strong signals");
break;
case 8:
System.out.print("Strong signals");
break;
case 9:
System.out.print("Extremely strong signals");
break;
}
System.out.print(".");
}
else {
System.out.print("请重新入数字：");
}
}
}
实在是改不明白了，请大家给点意见，谢谢啦
输出的内容前后顺序写反了？换下输出顺序看看，空格也没有吧
public static void main(String[] args) {
// TODO Auto-generated method stub
//初始化
System.out.println("请输入数字：");
Scanner in = new Scanner(System.in);
int S ;
int R ;
int number = in.nextInt();
if(number>=11&&number<=59)
{
R = number/10;
S = number%10;
switch(S) {
case 1:
System.out.print("Faint signals, barely perceptible");
break;
case 2:
System.out.print("Very weak signals");
break;
case 3:
System.out.print("Weak signals");
break;
case 4:
System.out.print("Fair signals");
break;
case 5:
System.out.print("Fairly good signals");
break;
case 6:
System.out.print("Good signals");
break;
case 7:
System.out.print("Moderately strong signals");
break;
case 8:
System.out.print("Strong signals");
break;
case 9:
System.out.print("Extremely strong signals");
break;
}
System.out.print(", ");
switch(R) {
case 1:
System.out.print("unreadable");
break;
case 2:
System.out.print("barely readable, occasional words distinguishable");
break;
case 3:
System.out.print("readable with considerable difficulty");
break;
case 4:
System.out.print("readable with practically no difficulty");
break;
case 5:
System.out.print("perfectly readable");
break;
}
System.out.print(".");
}
else {
System.out.print("请重新入数字：");
}
}