PHP：使用preg_ *函数获取数组

I want to parser and get a two-dimensional matrix using regular expresions of PHP. But I really don't know to parser and get a array(unidimensional). For example, I have this string:

    $str = {a}&{b}&{c}&{d&};

and I want to convert to array like this:

    array( 'a', 'b', 'c', 'd&' )

The pattern should be this:

    $pattern = '#(({[^}]+})(?:&(?1))*#';

The pattern matches correctly but I can't get all elements with $matches parameter:

    preg_match_all( $pattern, $str, $matches );
    print_r( $matches );

Output:

    Array
    (
        [0] => Array
            (
                [0] => {a}&{b}&{c}&{d&}
            )

        [1] => Array
            (
                [0] => a
            )

    )

I try to solve this problem involving the recursive pattern with parentheses.

    $pattern = '#(({[^}]+})(?:&((?1)))*#';

Output:

    Array
    (
        [0] => Array
            (
                [0] => {a}&{b}&{c}&{d&}
            )

        [1] => Array
            (
                [0] => a
            )

        [2] => Array
            (
                [0] => d&
            )

    )

Only is gotten the last element of array. The option flags PREG_PATTERN_ORDER or con PREG_SET_ORDER haven't solved my problem.

Is there any way to get the array of elements?

Greetings and thanks!

You can use this pattern which captures the content inside curly brackets and checks the syntax (i.e. {..}&{..}&{..}&{..}) :

preg_match_all('~\G{([^}]+)}(?:&|$)~', '{a}&{b}&{c}&{d&}', $result);

\G means "contiguous to a precedent match or at the start of the string". Thus, gaps are not allowed and the syntax is checked by the pattern.

The array you are looking for is $result[1]

Uh, your regex is way overcomplicated.

$pattern = "#{([^}]+)}#";
$data = "{a}&{b}&{c}&{d&}";
preg_match_all($pattern, $data, $matches);
print_r($matches);

Output:

Array
(
    [0] => Array
        (
            [0] => {a}
            [1] => {b}
            [2] => {c}
            [3] => {d&}
        )

    [1] => Array
        (
            [0] => a
            [1] => b
            [2] => c
            [3] => d&
        )

)

So your desired output is just $matches[1].

for your former question, try:

$str = "a&b&c&d&word";
$pattern = '/[^&]+/';
preg_match_all( $pattern, $str, $matches );
print_r( $matches );

get:

Array
(
    [0] => Array
        (
            [0] => a
            [1] => b
            [2] => c
            [3] => d
            [4] => word
        )
)