python循环统计

python循环统计9000-10000之间所有能被7整除，余2的数字

for i in range(9000, 10001):
    if i % 7 == 2:
        print(i)

lit = []
for i in range(9000, 10001):
    if i % 7 == 2:
        lit.append(i)
print(f"9000-10000之间所有能被7整除，余2的数字有 {len(lit)} 个,分别是 :")
print(",".join(str(x) for x in lit))

res = [i for i in range(9000, 10001) if i % 7 == 2]