我创建了两个网站( http://localhost/webone, http://localhost/webtwo).
第二个网站具有如下网址： http://localhost/webtwo/webone (使用ProxyPass和ProxyPassReverse)
如果我们转到上面的URL，上面就将会显示网络内容。 现在，如果有人访问一个Web，那么我想捕获用户访问URL。（可以是http：// localhost / webone或http：// localhost / webtwo / webone） 我的问题是： 如果有人从http：// localhost / webtwo / webone URL访问第二个网站。 然后，如果我执行以下代码，它将返回http：// localhost / webone。.
$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
但是浏览器显示的URL是http://localhost/webtwo/webone. 有人可以建议一种捕获URL的方法吗?http://localhost/webtwo/webone
You can add your custom request header by using RequestHeader directive to request headers list (right after ProxyPass*):
RequestHeader add X-REQUEST-URI "expr=%{HTTP_HOST}%{REQUEST_URI}"
This way you will have a header named HTTP_X_REQUEST_URI, a holder of requested URI and is accessible via $_SERVER['HTTP_X_REQUEST_URI']:
'HTTP_X_REQUEST_URI' => string 'localhost/webtwo/webone' (length=23)
Also there are some headers which are set by mod_proxy and you may find useful. From apache.org:
When acting in a reverse-proxy mode (using the
ProxyPassdirective, for example),mod_proxy_httpadds several request headers in order to pass information to the origin server. These headers are:X-Forwarded-For The IP address of the client.
X-Forwarded-Host The original host requested by the client in the Host HTTP request header.
X-Forwarded-Server The hostname of the proxy server.
ProxyPass adds X-Forwarded-Host header, which contains original host, and is accessible in php as $_SERVER['HTTP_X_FORWARDED_HOST'].
Your code can be something like this:
$host = $_SERVER['HTTP_HOST'];
if (!empty($_SERVER['HTTP_X_FORWARDED_HOST'])) {
$host = $_SERVER['HTTP_X_FORWARDED_HOST'];
}
$actual_link = "http://" . $host . $_SERVER['REQUEST_URI'];
When you are behind a Proxy:
Use $_SERVER['HTTP_X_FORWARDED_FOR'] in place of $_SERVER['REMOTE_ADDR']
Use $_SERVER['HTTP_X_FORWARDED_HOST'] and $_SERVER['HTTP_X_FORWARDED_SERVER']
in place of $_SERVER['SERVER_NAME']