Java程序设计编程
使用键盘录入技术，让用户输入年份和该年第一天是星期几，用0、1、2、3、4、5、6分别表示星期日、星期一、星期二、星期三、星期四、星期五、星期六，例如2023年的第一天是星期日，则用户依次输入2023和0，然后就可以在控制台打印出2023年各个月份的第一天是星期几。
提示和要求：
1.在统计2月的天数时，需要注意区分闰年和平年；
2.得到结果后，对照电脑上的日历检查一下结果是否正确。
具体思路怎么弄
望采纳，不懂可以私聊。
import java.util.Scanner;
public class Test06 {
public static void main(String[] args) {
int year = 2023;
int day = 0;
final Scanner scanner = new Scanner(System.in);
System.out.println("请输入年");
year = scanner.nextInt();
System.out.println("该年第一天是星期几");
day = scanner.nextInt();
final String[] data = {"日", "一", "二", "三", "四", "五", "六"};
System.out.println("1月的第一天是:" + data[day]);
final int[] ints = {31, year % 4 == 0 ? 29 : 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
for (int i = 0; i < 11; i++) {
day += ints[i] % 7;
day = day < 7 ? day : day - 7;
System.out.println(i + 2 + "月的第一天是:" + data[day]);
}
}
}
如有帮助，望采纳
year = eval(input("请输入年份:"))
day = eval(input("请输入该年的第一天是星期几:"))
lst1 = ["January","February","March","April","May","June","July","August","September","October","November","December"]
def is_leapyear(year):
if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0:
return True
else:
return False
if is_leapyear(year):
for j in range(1,13):
print(" %d,%s"%(year,lst1[j-1]))
print("Sun Mon Tue Wed Thr Fri Sat ")
print(" " * day,end = "")
if j == 1 or j == 3 or j == 5 or j == 7 or j == 8 or j == 10 or j == 12:
for i in range(1,32):
print(format(str(i),"4s"),end = "")
if (i + day) % 7 == 0:
print()
day =(i + day) % 7
print()
elif j == 2:
for k in range(1,30):
print(format(str(k),"4s"),end = "")
if (k + day) % 7 == 0:
print()
day =(k + day) % 7
print()
else :
for l in range(1,31):
print(format(str(l),"4s"),end = "")
if (l + day) % 7 == 0:
print()
day =(l + day) % 7
print()
else:
for a in range(1,13):
print(" %d,%s"%(year,lst1[a-1]))
print("Sun Mon Tue Wed Thr Fri Sat ")
print(" " * day,end = "")
if a == 1 or a == 3 or a == 5 or a == 7 or a == 8 or a == 10 or a == 12:
for z in range(1,32):
print(format(str(z),"4s"),end = "")
if (z + day) % 7 == 0:
print()
day =(z + day) % 7
print()
elif a == 2:
for x in range(1,29):
print(format(str(x),"4s"),end = "")
if (x + day) % 7 == 0:
print()
day =(x + day) % 7
print()
else :
for c in range(1,31):
print(format(str(c),"4s"),end = "")
if (c + day) % 7 == 0:
print()
day =(c + day) % 7
print()
import java.util.Scanner;
public class dome5 {
public static void main(String[] args) {
try(Scanner input = new Scanner(System.in);) {
System.out.print("Enter year and number represented as someday "+
"of week (1 - 7): ");
showDay(input.nextInt(), input.nextInt());
}
}
//显示每月第一天是星期几
public static void showDay(int year, int day) {
String[] months = {"一月", "二月", "三月", "四月", "五月", "六月",
"七月", "八月", "九月", "十月", "十一月",
"十二月"};
for (int i = 0; i < months.length; i++)
System.out.printf("%d的%s是%s\n", year,months[i],
day(year, i + 1, 1));
}
//某天是星期几
public static String day(int year, int month, int day) {
String[] days = {"星期日", "星期六", "星期一", "星期二", "星期三",
"星期四", "星期五"};
int m = month,k, j;
if(month < 1 || month > 12) //如果月份不合法，抛出异常
throw new IllegalArgumentException("Error Month: "+month);
if(day < 1 || day > 31) //如果天数不合法，抛出异常
throw new IllegalArgumentException("Error Day: "+day);
if(month == 1 || month == 2) { //处理月份为1或2的情况
m = (month == 1) ? 13 : 14; //如果月份为1，m = 13；否则，m = 14
year--; //年份减一
}
k = year % 100; //世纪的第几年
j = Math.abs(year / 100); //世纪数
int h = (day + (26 * (m + 1)) / 10 + k + (k / 4) + (j / 4) + 5 * j) % 7;
return days[h];
}
}
代码:
package pack2;
import java.util.Scanner;
public class DayIs {
public static void main(String[] args) {
try(Scanner input = new Scanner(System.in);) {
System.out.print("Enter year and number represented as someday "+
"of week (0 - 6): ");
showDay(input.nextInt(), input.nextInt());
}
}
//显示每月第一天是星期几
public static void showDay(int year, int day) {
String[] months = {"January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November",
"December"};
for (int i = 0; i < months.length; i++)
System.out.printf("%10s 1, %d is %s\n", months[i], year,
day(year, i + 1, 1));
}
//某天是星期几
public static String day(int year, int month, int day) {
String[] days = {"Saturday", "Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday"};
int m = month,k, j;
if(month < 1 || month > 12) //如果月份不合法，抛出异常
throw new IllegalArgumentException("Error Month: "+month);
if(day < 1 || day > 31) //如果天数不合法，抛出异常
throw new IllegalArgumentException("Error Day: "+day);
if(month == 1 || month == 2) { //处理月份为1或2的情况
m = (month == 1) ? 13 : 14; //如果月份为1，m = 13；否则，m = 14
year--; //年份减一
}
k = year % 100; //世纪的第几年
j = Math.abs(year / 100); //世纪数
int h = (day + (26 * (m + 1)) / 10 + k + (k / 4) + (j / 4) + 5 * j) % 7;
return days[h];
}
}
Scanner 输入，if判断
package demo;
import java.util.Scanner;
public class practice {
static int year;
public static void main(String[] args) {
//接收用户的输入
Scanner input=new Scanner(System.in);
System.out.print("Enter the year and the date: \n");
year = input.nextInt();
int date = input.nextInt();
//调用函数
PrintDate(date);
}
//判断是否闰年
public static boolean IsLeapYear(int year) {
if((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
return true;
else return false;
}
//返回该月的天数
public static int Days(int month) {
switch(month) {
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:return 31;
case 2:
if(IsLeapYear(year)) {
return 29;
}else {
return 28;
}
case 4:
case 6:
case 9:
case 11:return 30;
default:
return 0;
}
}
//打印月历分割线+周英文简写
public static void PrintMonthHead() {
System.out.print("_________________________________\n");
System.out.print("Sun Mon Tue Wed Thu Fri Sat");
System.out.print("\n");
}
//打印日历
public static void PrintDate(int date) {
//count表示月历开头的空隔天数
int count = date == 7 ? 0 : date;
for(int i = 1;i < 13;i ++) {
//打印月历表头
System.out.print(" " + i + "月\n");
//打印月历分割线+周英文简写
PrintMonthHead();
//打印月历开头的空隔
if(count != 0)
for(int j = 0;j < count;j++)
System.out.print(" ");
//打印日历具体内容
for(int k = 1;k <= Days(i);k ++) {
if(k < 10) System.out.print( k + " ");
if(k >= 10) System.out.print( k + " ");
count ++;
//累计满7天，换行
if(count % 7 == 0) System.out.print("\n");
}
//计算下个月的月历开头的空隔天数
count = ((count - 1) % 7) + 1 == 7 ? 0 : ((count - 1) % 7) + 1;
//两个月之间换两行
System.out.print("\n \n");
}
}
}