Python面向对象编程——生成多项式的一阶导数

Python面向对象编程

输入多项式，生成多项式的一阶导数

template

#### Please do not use input() function!!!
import random


class process_derivative(object):

    def __init__(self, polynominal):
        self.polynominal = polynominal


    def get_first_derivative(self):
        # You should follow the example format. Do not use input()
        result_two = 'your calculator result'
        return "The first derivative is:" + result_two  # e.g. "The first derivative is: '6*x^2+6*x+5'"

######要求：
1、输入的多项式只包含一个变量，变量可以是任意英文字母，不一定是x
2、不需要按照次数升高或降低的方式排列
3、系数需位于变量前
4、不存在次数相同的两项（输入的多项式必须是合并同类项后的结果）

######疑问：
如何判断只有一个变量？
如何分割不同的项？
如何把项的幂提取出来？

不知道下面代码能否满足你的要求：
测试结果如下：

#### Please do not use input() function!!!
import random
import re


class process_derivative(object):

    def __init__(self, polynominal):
        self.polynominal = polynominal


    def get_first_derivative(self):
        b = self.polynominal
        letter = re.search('[a-zA-Z]+', b)[0]

        res = re.findall(f"(\d+)\*{letter}\^*(\d*)", b)
        symbol = re.findall("[+-]{1}", b)

        str1 = ''
        for index, coef in enumerate(res):
            num = coef[0]
            i = coef[1]
            if i:
                coef1 = int(num) * int(i)
                if int(i) - 1 == 1:
                    str2 = "{}*{}".format(coef1, letter)
                else:
                    str2 = "{}*{}^{}".format(coef1, letter, int(i) - 1)
            else:
                coef1 = int(num)
                str2 = "{}".format(coef1)
            str1 += str2
            if index >= 0 and index < len(symbol) and i:
                str1 += symbol[index]
        # You should follow the example format. Do not use input()
        result_two = str1
        return "The first derivative is:" + result_two  # e.g. "The first derivative is: '6*x^2+6*x+5'"
a = process_derivative('2*x^3+3*x^2+5*x+1')
print(a.get_first_derivative())

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PAT编程（python） 1010 一元多项式求导
https://blog.csdn.net/qq_44614636/article/details/127039968