如何用列表储存count的值呢？不要count被零覆盖后的
我的代码：n=int(input()) count=0 l=[] for i in range(n): a,b=input().split() a=int(a) b=int(b) if 90<=a<=140 and 60<=b<=90: count+=1 else: l.append(count) count= 0 print(max(l))}
我的代码：n=int(input()) count=0 l=[] for i in range(n): a,b=input().split() a=int(a) b=int(b) if 90<=a<=140 and 60<=b<=90: count+=1 else: l.append(count) count= 0 print(max(l))}