求用C语言数组编程(需要完整且正确的程序)

用数组编程寻找既是完全平方数,又有两位数字相同的三位正整数,例如121.144等。要求统计满足该条件的整数个数，并从大到小打印这些整数

马上开写

#include<stdio.h>
#include<math.h>

int main(){
int  num[100];
int i,j,index,a,b,c;
for(i=10,j=0;i<=31;i++)
{
       index=i*i;
        a = index / 100;
        b = (index/ 10) % 10;
        c = index % 10;
        if (a == b || a == c || b == c)
        {
        num[j]=index;
        j++;
        }
}
printf("个数为：%d\n",j);
for(i=0;i<j;i++)
{
printf("%d ",num[i]);


}

return 0;
}

 vector<int>vv;//存放符合条件的数
 int cout = 0;//符合条件个数
 for (int i = 999; i >= 100; --i)
 {
     int m = floor(sqrt(i) + 0.5);
     if (m * m == i)//完全平方数判断
     {
         int a = i % 10;
         int b = i / 10 % 10;
         int c = i / 100 % 10;
         if ((a == b)||(b == c)||(c == a))//两个相同数判断
         {
             vv.push_back(i);
             cout++;
         }
     }   
 }
 printf("符合条件个数:%d\n", cout);
 printf("从大到小排序:\n");
 for (int j = 0; j < vv.size(); j++)
 {
     printf("%d\n", vv[j]);
 }

#include <stdio.h>
#include <math.h>
int main()
{
    int i;
    int count = 0;
    for (i = 999; i >= 100; i--)
    {
        if (i == (int)sqrt(i) * (int)sqrt(i))
        {
            int a = i % 10;
            int b = i /10% 10;
            int c = i /100% 10;
            if ((a == b) + (b == c) + (c == a)==1)
            {
                printf("%d\n", i);
                count++;
            }

        }
    }
    printf("个数：%d", count);
    return 0;
}

#include <stdio.h>

int main()
{
    int arr[900];
    int i, j, n = 0, a, b, c;
    for (i = 100; i < 1000; i++)
    {
        a = i / 100;
        b = (i / 10) % 10;
        c = i % 10;
        if (a == b || a == c || b == c)
        {
            j = sqrt(i);
            if (j * j == i)
                arr[n++] = i;
        }
    }
    printf("%d\n", n);
    for (i = n - 1; i >= 0; i--)
        printf("%d ", arr[i]);

  

代码参考：

#include <stdio.h>
#include <math.h>
int func(int);
int func(int x)
{
    int i;
    int count=0;
    int t1,t2,t3;
    for(i=101;i<=x;i++)
    {
        if(sqrt(i)==(int)sqrt(i))
        {
            t1=i%10;
            t2=i/10%10;
            t3=i/100;
            if(t1==t2||t2==t3||t1==t3)
                count++;    
        }
    }
    return count;
}
int main()
{
    int x;
    scanf("%d",&x);
    printf("%d",func(x));
    return 0;
}