python列表元组题

帮帮忙吧！真是没思路了，都试了好多遍了，没结果。学不会了，提供一个思路吧

对您有帮助，请点击我的回答左下角
“采纳该答案”

一、诗歌排版用zip()打包诗句

#!/usr/bin/nve python
# coding: utf-8

# data 准备
title = '︿︿小︿池︿︿' # 凑够诗句长度。
author = '＊宋／杨万里＊' # 凑够诗句长度。
first = '泉眼无声惜细流'
second = '树荫照水爱晴柔'
third = '小荷才露尖尖角'
fourth = '早有蜻蜓立上头'

# 拼接处理
poem = map(lambda x: '  '.join(x), zip(fourth, third, second, first, author, title))

# 轮询输出
print(f"\n\n{'':~^50}\n\n")

for line in poem:
    print(f"{line:^43}")

print(f"\n\n{'':~^50}\n\n")

二、矩阵对角和用二维数组下标

#!/usr/bin/nve python
# coding: utf-8


# 输入
scores = [] # 成绩列表。

for i in 'ab':
    a, b = map(int, input(f"\n{'输入分数(如1 5)：':>15}").split())
    scores.append((a, b))


# 轮询输出
print(f"\n\n{'':~^50}\n\n{' 成绩矩阵 ':*^46}")

for i in scores:
    print(f"\n{i[0]:>23}{i[1]:>4}")

print(f"\n{'*'*50}\n\n{'主对角线和：':>17}{scores[0][0] + scores[1][1]}，次对角线和：{scores[0][1] + scores[1][0]}\n\n{'':~^50}\n\n")

由于有倍受高版本Python推崇的“插值字符串格式化”(个人觉得，用起来就就像自然语言一样“得心应手”，一段输出都可以一条语句搞定🤗)好用，代码中就不用新式字符串格式化了。

'成绩一：{}，成绩二：{}'.format(98， 67)

对您有帮助，请点击左边
“采纳该答案”

m = eval(input())

prime = 0
secondary = 0
for i in range(len(m)):
    prime += m[i][i]
    secondary += m[i][len(m)-i-1]

print("主对角线之和={}".format(prime))
print("次对角线之和={}".format(secondary))


class Solution(object):
    def __init__(self):
        pass

    def sum_main_diagonal(self, mytuple):
        mysum = 0
        width = len(mytuple[0])
        height = len(mytuple)
        if width != height:
            mysum = mytuple[0][0] + mytuple[-1][-1]
        else:
            for i in range(width):
                mysum += mytuple[i][i]
        return mysum

    def sum_minor_diagonal(self, mytuple):
        mysum2 = 0
        width = len(mytuple[0])
        height = len(mytuple)
        if width != height:
            mysum2 += mytuple[0][-1] + mytuple[-1][0]
        else:
            for i in range(width):
                mysum2 += mytuple[i][width - 1 - i]
        return mysum2


if __name__ == "__main__":
    s = Solution()
    mytuple = eval(input())
    print("主对角线之和={}".format(s.sum_main_diagonal(mytuple)))
    print("次对角线之和={}".format(s.sum_minor_diagonal(mytuple)))