
初学者怎么做?大家指点指点思路。(在3个候选人中进行投票,统计他们的票数)
#include <stdio.h>
int main()
{
int n, count = 0, a = 0, b = 0, c = 0, xcnt = 0;
while (1)
{
scanf("%d", &n);
if (n == -1)
break;
if (n == 1)
a++;
if (n == 2)
b++;
if (n == 3)
c++;
if (n >= 1 && n <= 3)
xcnt++; // 有效票
count++; //所有票
}
printf("A=%d\n", a);
printf("B=%d\n", b);
printf("C=%d\n", c);
printf("Tot=%d\n", xcnt);
if (a * 1.0 / count > 0.5)
printf("A-yes");
else if (b * 1.0 / count > 0.5)
printf("B-yes");
else if (c * 1.0 / count > 0.5)
printf("C-yes");
else
printf("all-NO"); //题目结果是按所有票统计的,因此为No
return 0;
}
#include<stdio.h>
void main()
{
int k=0,suma=0,sumb=0,sumc=0,count=0;
while(1)
{
scanf("%d ",&k);
if((k>=1)&&(k<=3))
{
switch (k)
{
case 1:suma++;break;
case 2:sumb++;break;
case 3:sumc++;break;
}
count++;
}
else if(k==-1)
break;
}
printf("A=%d\n",suma);
printf("B=%d\n",sumb);
printf("C=%d\n",sumc);
printf("Tot=%d\n",count);
if(suma>count/2)
printf("A-yes\n");
if(sumb>count/2)
printf("B-yes\n");
if(sumc>count/2)
printf("C-yes\n");
if((suma<=count/2)||(sumb>count/2)||(sumc>count/2))
printf("all-NO\n");
}
仅供参考!