下面这个代码有什么问题？

#include
#include

int main(void)
{
struct stu{
int num;
char*name;
char sex;
float score;
}boy1,boy2;

printf("please input ID and name\n");
scanf("%d%s",&boy1.num,boy1.name);

printf("input sex and score\n");
scanf("%c %f",&boy1.sex,boy1.score);

boy2=boy1;

printf("Number=%d\nName=%s\n",boy2.num,boy2.name);
printf("Sex=%c\nScore=%f\n",boy2.sex,boy2.score);

system("PAUSE");


return 0;

}

详细地说一下这个代码有什么问题。谢谢

（1）结构体的name没有分配内存
（2）读取成绩的时候漏写了&
（3）读取性别前，需要用getchar()吸收一下上一次输入的回车符

代码修改如下：

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    struct stu {
        int num;
        char* name;
        char sex;
        float score;
    }boy1, boy2;

    boy1.name = (char*)malloc(20); //申请内存空间
    
    printf("please input ID and name\n");
    scanf("%d%s", &boy1.num, boy1.name);
    getchar(); //吸收回车符
    printf("input sex and score\n");
    scanf("%c %f", &boy1.sex, &boy1.score); //boy1.score前面加&

    boy2 = boy1;

    printf("Number=%d\nName=%s\n", boy2.num, boy2.name);
    printf("Sex=%c\nScore=%f\n", boy2.sex, boy2.score);

    system("PAUSE");


    return 0;
}

char*name; 改成 char name[20]这样子，你没有给name分配空间，所以scanf输入时会崩溃掉的

#include <stdio.h>
#include <stdlib.h>
int main(void)
{
struct stu{
int num;
char name[20];  //name定义为字符数组，需要分配空间才行
char sex;
float score;
}boy1,boy2;

printf("please input ID and name\n");
scanf("%d%s",&boy1.num,boy1.name);
getchar();  //要加这一句，否则sex接收的是换行符
printf("input sex and score\n");
scanf("%c %f",&boy1.sex,&boy1.score);   //score前面也要加&

boy2=boy1;

printf("Number=%d\nName=%s\n",boy2.num,boy2.name);
printf("Sex=%c\nScore=%f\n",boy2.sex,boy2.score);

system("PAUSE");


return 0;
}

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