用函数以及指针来解决问题
这个是题目所要求的内容，要求用指针和函数来解决问题，大家看看该怎么做呢，对我来说有点困难
按照题目要求定义一维数组和二维数组，然后用指针访问数组元素
二维数组访问用行指针，之前给你写过代码，跟那个是一样的
代码如下：
#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <string.h>
void display(long* num, char(*name)[10], char(*cn)[10], float(*score)[3], int n)
{
int i, j;
float* tmp;
printf("%-10s %-10s %-10s %-10s %-10s\n", "No.", "Name", "Computer", "Math", "English");
for (i = 0; i < n; i++)
{
printf("%-10d %-10s", *(num + i), *(name + i));
tmp = *(score + i);
for (j = 0; j < 3; j++)
printf(" %-10.1f", *(tmp + j));
printf("\n");
}
}
void query(long* num, char(*name)[10], char(*cn)[10], float(*score)[3], int n)
{
int i, j, flag = 0;
long id;
float* tmp;
printf("input a student ID: ");
scanf("%ld", &id);
for (i = 0; i < n; i++)
{
if (id == *(num + i))
{
flag = 1; //表示找到，输出学生信息
printf("%-10s %-10s %-10s %-10s %-10s\n", "No.", "Name", "Computer", "Math", "English");
printf("%-10d %-10s", *(num + i), *(name + i));
tmp = *(score + i);
for (j = 0; j < 3; j++)
printf(" %-10.1f", *(tmp + j));
printf("\n");
break;
}
}
if (flag == 0)
printf("No such student\n"); //提示学生不存在
}
void update(long* num, char(*name)[10], char(*cn)[10], float(*score)[3], int n)
{
int i, j, flag = 0;
long id;
float* tmp, sc;
char kc[10] = { 0 };
printf("input a student ID: ");
scanf("%ld", &id);
printf("input course name: ");
scanf("%s", kc);
for (i = 0; i < n; i++)
{
if (id == *(num + i))
{
flag = 1; //表示找到，输出学生信息
printf("please input a score: ");
scanf("%f", &sc);
tmp = *(score + i);
for (j = 0; j < 3; j++)
{
if (strcmp(kc, *(cn + j)) == 0)
{
flag = 2;
*(tmp + j) = sc;
break;
}
}
break;
}
}
if (flag == 0)
printf("No such student\n"); //提示学生不存在
else if (flag == 1)
printf("No such course\n"); //提示没有这门课程
else
display(num, name, cn, score, n);
}
void remove(long* num, char(*name)[10], char(*cn)[10], float(*score)[3], int* n)
{
int i, j, k, flag = 0;
long id;
float* tmp1, * tmp2;
printf("input a student ID: ");
scanf("%ld", &id);
for (i = 0; i < *n; i++)
{
if (id == *(num + i))
{
flag = 1; //表示找到，输出学生信息
//前移
for (j = i; j < *n - 1; j++)
{
*(num + j) = *(num + j + 1);
strcpy(*(name + j), *(name + j + 1));
tmp1 = *(score + j);
tmp2 = *(score + j + 1);
for (k = 0; k < 3; k++)
*(tmp1 + k) = *(tmp2 + k);
}
*n = (*n) - 1;
break;
}
}
if (flag == 0)
printf("No such student\n"); //提示学生不存在
else
display(num, name, cn, score, *n); //显示删除后的信息
}
void add(long* num, char(*name)[10], char(*cn)[10], float(*score)[3], int* n)
{
int i, flag = 0;
long id;
float* tmp;
int n2 = *n;
while (1)
{
printf("input a student ID: ");
scanf("%ld", &id);
for (i = 0; i < n2; i++)
{
if (id == *(num + i))
{
flag = 1; //表示找到，输出学生信息
break;
}
}
if (flag == 0)
break;
else
printf("the Id has exist, please ");
}
*(num + n2) = id;
printf("input student name: ");
scanf("%s", *(name + n2));
tmp = *(score + n2);
printf("input Computer score: ");
scanf("%f", (tmp + 0));
printf("input Math score: ");
scanf("%f", (tmp + 1));
printf("input English score: ");
scanf("%f", (tmp + 2));
*n = (*n) + 1; //学生数量+1
display(num, name, cn, score, *n);
}
int main()
{
char c;
long num[20] = { 20210101,20210102,20210103,20210104 };
char name[20][10] = { "Stu_01","Stu_02","Stu_03","Stu_04" };
char courseName[3][10] = { "Computer","Math","English" };
float score[20][3] = { {60.5,97.0,90.5},{88.5,67.5,88.1},{72.3,75.0,92.0} ,{66.8,86.0,45.5} };
int stuNmb = 4; //学生数量
printf("d. show all information\n");
printf("q. search students' scores according to student ID numbers\n");
printf("u. modify the students' scores according to student ID numbers and course name\n");
printf("r. delete the students' information according to student ID numbers\n");
printf("a. add a student's information\n");
printf("e. exit\n");
while ((c = getchar()) != 'e') //input e to end the program
{
if (c == 'd')
{
display(num, name, courseName, score, stuNmb);
}
else if (c == 'q')
{
query(num, name, courseName, score, stuNmb);
}
else if (c == 'u')
{
update(num, name, courseName, score, stuNmb);
}
else if (c == 'r')
{
remove(num, name, courseName, score, &stuNmb);
}
else if (c == 'a')
{
add(num, name, courseName, score, &stuNmb);
}
}
return 0;
}
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