想问一下,如何将这个服务端代码改成一直运行接收树莓派客户端的图片(本人刚接触编程)
# -*- coding: UTF-8 -*-
from imageai.Prediction import ImagePrediction
import socket
import os
import sys
import struct
import time
def socket_service():
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind(('192.168.1.101', 6666))
s.listen(10)
except socket.error as msg:
print(msg)
sys.exit(1)
print("Wait")
while True:
sock, addr = s.accept()
deal_data(sock, addr)
break
s.close()
def deal_data(sock, addr):
print("Accept connection from {0}".format(addr))
while True:
fileinfo_size = struct.calcsize('128sl')
buf = sock.recv(fileinfo_size)
if buf:
filename, filesize = struct.unpack('128sl', buf)
fn = filename.decode().strip('\x00')
new_filename = os.path.join('./', 'new_' + fn)
recvd_size = 0
fp = open(new_filename, 'wb')
while not recvd_size == filesize:
if filesize - recvd_size > 1024:
data = sock.recv(1024)
recvd_size += len(data)
else:
data = sock.recv(1024)
recvd_size = filesize
fp.write(data)
fp.close()
sock.close()
break
if __name__ == '__main__':
socket_service()
去掉break
,你的代码循环执行一次就break掉了。