class类下定义函数引用mysql.connector.connect报错

问题遇到的现象和发生背景

想封装个类来作为读写数据库的类，然后就报错了

用代码块功能插入代码，请勿粘贴截图

class mysql_tools():
    def __init__(self, baseinfo):
        print(baseinfo)
        self.host = baseinfo.split('-')[2]
        self.user = baseinfo.split('-')[0]
        self.password = baseinfo.split('-')[1]
        self.database = baseinfo.split('-')[3]

        self.dbinfo = "mysql+pymysql://" + self.user + ":" + self.password + "@" + self.host + "/" + self.database + "?charset=utf8"

    def get_sql_data(self, sql):
        mydb = mysql.connector.connect(HOST=self.host, USER=self.user, PASSWORD=self.password, DATABASE=self.database)
        cursor = mydb.cursor()
        print(sql)
        cursor.execute(sql)
        result = cursor.fetchall()
        return result

if __name__ == '__main__':
    tl = mysql_tools(baseinfo="marker-123456-localhost-markdata")
    print(tl.dbinfo)
    re = tl.get_sql_data("select * from stock_all_oneday_data")
    print(re)

运行结果及报错内容

Traceback (most recent call last):
  File "C:/Users/connect_mysql.py", line 50, in 
    re = tl.get_sql_data("select * from stock_all_oneday_data")
  File "C:/Users/connect_mysql.py", line 39, in get_sql_data
    mydb = mysql.connector.connect(HOST=self.host,USER=self.user,PASSWORD=self.password,DATABASE=self.database)
  File "D:\anaconda3\lib\site-packages\mysql\connector\__init__.py", line 264, in connect
    return CMySQLConnection(*args, **kwargs)
  File "D:\anaconda3\lib\site-packages\mysql\connector\connection_cext.py", line 80, in __init__
    self.connect(**kwargs)
  File "D:\anaconda3\lib\site-packages\mysql\connector\abstracts.py", line 963, in connect
    self.config(**kwargs)
  File "D:\anaconda3\lib\site-packages\mysql\connector\abstracts.py", line 502, in config
    raise AttributeError("Unsupported argument '{0}'".format(key))
AttributeError: Unsupported argument 'HOST'

我的解答思路和尝试过的方法

没想明白