c++第七章程序设计
731题与737题c++怎么做 学的是一维数组和c字符串难 最好易懂的
比较指针或者用数据结构链表算法
1
#include<stdio.h>
void main(){
int a[10];
int b[10];
int a1,a2;
printf("请输入第1个数组的10个整数\n");
for(int i=0;i<10;i++){
scanf("%d",&a1);
a[i]=a1;
}
printf("请输入第2个数组的10个整数\n");
for(int i=0;i<10;i++){
scanf("%d",&a2);
b[i]=a2;
}
for(int i=0;i<10;i++){
for(int j=0;j<10;j++){
if(a[i]==b[j])
printf("%d ",a[i]);
}
}
}
2
#include <iostream>
using namespace std;
const int num1 = 26; //num1=letters
const int num2 = 99; //num2=string
void countLetters(const char list[],int counts[])
{
for(int i=0;i<num1;i++)
counts[i]=0;
for(int j=0;j<num2;j++)
{
counts[list[j]-'a']++;
counts[list[j]-'A']++;
}
}
void displayCounts(const int counts[])
{
for (int i=0;i<num1;i++){
if(counts[i]!=0)
cout<<static_cast<char>(i+'a')<<" : "<<counts[i]<<" times "<<endl;
}
}
int main()
{
char list[num2];
int counts[num1];
cout<<"Enter a string : ";
cin.getline(list,num2);
countLetters(list,counts);
displayCounts(counts);
return 0;
}
代码如下，有帮助的话采纳一下哦！
7.31
#include<stdio.h>
void main(){
int a[10];
int b[10];
int a1,a2;
printf("请输入第1个数组的10个整数\n");
for(int i=0;i<10;i++){
scanf("%d",&a1);
a[i]=a1;
}
printf("请输入第2个数组的10个整数\n");
for(int i=0;i<10;i++){
scanf("%d",&a2);
b[i]=a2;
}
for(int i=0;i<10;i++){
for(int j=0;j<10;j++){
if(a[i]==b[j])
printf("%d ",a[i]);
}
}
}
7.37
#include <iostream>
using namespace std;
const int num1 = 26; //num1=letters
const int num2 = 99; //num2=string
void countLetters(const char list[],int counts[])
{
for(int i=0;i<num1;i++)
counts[i]=0;
for(int j=0;j<num2;j++)
{
counts[list[j]-'a']++;
counts[list[j]-'A']++;
}
}
void displayCounts(const int counts[])
{
for (int i=0;i<num1;i++){
if(counts[i]!=0)
cout<<static_cast<char>(i+'a')<<" : "<<counts[i]<<" times "<<endl;
}
}
int main()
{
char list[num2];
int counts[num1];
cout<<"Enter a string : ";
cin.getline(list,num2);
countLetters(list,counts);
displayCounts(counts);
return 0;
}
第一题：
#include<iostream>
#include<string>
using namespace std;
void function1(){
string s1;
string s2;
cout<<"Enter list1:";
getline(cin, s1);
cout<<"Enter list2:";
getline(cin, s2);
string temp = "";
string arr1[10];
string arr2[10];
int index = 0;
for(int i=0;i<s1.size();i++){
if(s1[i]==' '){
arr1[index] = temp;
temp = "";
index++;
}else{
temp+=s1[i];
}
}
arr1[index] = temp;
temp = "";
index = 0;
for(int i=0;i<s2.size();i++){
if(s2[i]==' '){
arr2[index] = temp;
temp = "";
index++;
}else{
temp+=s2[i];
}
}
arr2[index] = temp;
cout<<"The common elements are ";
for(int i=0;i<10;i++){
for(int j=0;j<10;j++){
if(arr1[i]==arr2[j]){
cout<<arr1[i]<<" ";
}
}
}
}
int main(int argc, char const *argv[])
{
function1();
return 0;
}
第二题：
#include<iostream>
using namespace std;
void count(const char s[], int counts[]){
int index=0;
while(s[index]!='\0'){
if(s[index]==' '){
index++;
continue;
}
else if(int(s[index])>=65 && int(s[index])<=90){
counts[int(s[index])-65]++;
}else if(int(s[index])>=97 && int(s[index])<=122){
counts[int(s[index])-97]++;
}
index++;
}
for(int i=0;i<26;i++){
if(counts[i]!=0){
cout<<char(i+97)<<": "<<counts[i]<<" times"<<endl;
}
}
}
int main(int argc, char const *argv[])
{
int count_arr[26]={0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
char arr[100] = "Welcome to New York!";
count(arr, count_arr);
return 0;
}
第一题：
#include<iostream>
using namespace std;
int main()
{
int i,n,a,b;
int num1[11],num2[11];
for(i=1;i<=10;i++)
{
cin>>a;
num1[i]=a;
} //为num1数组添加元素
for(n=1;n<=10;n++)
{
cin>>b;
num2[n]=b;
} //为num2数组添加元素
for(i=1;i<=10;i++)
{
for(n=1;n<=10;n++)
{
if(num1[i]==num2[n])
{
cout<<num1[i]<<endl;
break;
}
}
}
return 0;
}
第二题：
#include <iostream>
using namespace std;
const int num1 = 26; //num1=letters
const int num2 = 99; //num2=string
void countLetters(const char list[],int counts[])
{
for(int i=0;i<num1;i++)
counts[i]=0;
for(int j=0;j<num2;j++)
{
counts[list[j]-'a']++;
counts[list[j]-'A']++;
}
}
void displayCounts(const int counts[])
{
for (int i=0;i<num1;i++){
if(counts[i]!=0)
cout<<static_cast<char>(i+'a')<<" : "<<counts[i]<<" times "<<endl;
}
}
int main()
{
char list[num2];
int counts[num1];
cout<<"Enter a string : ";
cin.getline(list,num2);
countLetters(list,counts);
displayCounts(counts);
return 0;
}
如有帮助，还请采纳！谢谢！
#include<stdio.h>
int main(){
int list1[10];
int list2[10];
int list3[10];//用来保存相同数字的数组
int a=-1;//表示list3长度
//获取list1
printf("Enter list1: ");
for(int i=0;i<10;i++)
scanf("%d",&list1[i]);
//获取list2
printf("Enter list2: ");
for(int i=0;i<10;i++){
scanf("%d",&list2[i]);
//每次都用list2[i]去和list1的每一项比较。
for(int j=0;j<10;j++){
//如果相等，就把相等数放在list3中。
if(list1[j]==list2[i]){
a++;//a是下标
list3[a]=list2[i];
}
}
}
//这时list3中有a个数，把他们遍历输出。
printf("The common elements are");
for(;a>=0;a--)
printf(" %d",list3[a]);
}