问题：有N个学生的信息，要求按照成绩的高低顺序输出各学生的信息

问题遇到的现象和发生背景

问题：有N个学生的信息，要求按照成绩的高低顺序输出各学生的信息
不知道错在哪，不能正常输出

用代码块功能插入代码，请勿粘贴截图
#include
#define N 5

int main()
{
    struct Student
    {
        int num;
        char name[20];
        float score;
    };

    struct Student stu[5] = { {10101, "Zhang", 78}, {10103, "Wang", 98.5}, {10106, "Li", 86}, {10108, "Ling", 73.5}, {10110, "Sun", 100} };
    int  i, j;
    struct Student t;
    for (i = 0; i < N - 1; i++)
    {
        for (j = i + 1; j < N; i++)
        {
            if (stu[i].score < stu[j].score)
            {
                t = stu[j];
                stu[j] = stu[i];
                stu[i] = t;
            }
        }
    }
    for (i = 0; i < N; i++)
    {
        printf("%d\t%s\t%.2f\n", stu[i].num, stu[i].name, stu[i].score);
    }
    return 0;
}
运行结果及报错内容

if 那里显示访问异常


#include <stdio.h>
struct Student{
    int num;
    char name[20];
    float score;
};
int main(){
    struct Student stu[5]={{10101,"Zhang",78},{10103,"Wang",98.5},{10106,"Li",86},{10108,"Ling",73.5},{10110,"Sun",100}};
    struct Student temp;
    int n=5;
    int i,j,k;
    printf("由高到低排名：\n");
    for(i=0;i<n-1;i++){
        k=i;
        for(j=i+1;j<n;j++)
            if(stu[j].score>stu[k].score)
                k=j;
            temp=stu[k];
            stu[k]=stu[i];
            stu[i]=temp;
    }
    for(i=0;i<n;i++)
        printf("%d%8s%8.2f\n",stu[i].num,stu[i].name,stu[i].score);
    return 0;
}

冒泡排序，修改如下：

#include<stdio.h>
#define N 5
int main()
{
    struct Student
    {
        int num;
        char name[20];
        float score;
    };
    struct Student stu[5] = { {10101, "Zhang", 78}, {10103, "Wang", 98.5}, {10106, "Li", 86}, {10108, "Ling", 73.5}, {10110, "Sun", 100} };
    int  i, j;
    struct Student t;
    for (i = 0; i < N - 1; i++)
    {
        for (j = 0; j < N-1-i; j++)
        {
            if (stu[j].score < stu[j+1].score)
            {
                t = stu[j];
                stu[j] = stu[j+1];
                stu[j+1] = t;
            }
        }
    }
    for (i = 0; i < N; i++)
    {
        printf("%d\t%s\t%.2f\n", stu[i].num, stu[i].name, stu[i].score);
    }
    return 0;
}