python输出特殊图形

for i in range(1,x+1):
    for j in range(1,x+1-i):
        print(" ",end=" ")
    for k in range(1,2*i):
        print("*",end=" " )

print(func1(3))

• • • • • • • • • None
                  求在源代码上修改一下 输出等腰三角

def fun(x):
    for i in range(1,x+1):
        print(' '*(x-i),end='')
        print('*'*(2*i-1))
fun(5)

for i in range(1,x+1):
    for j in range(1,x+1-i):
        print(" ",end=" ")
    for k in range(1,2*i):
        print("*",end=" " )
    print()
func1(3)

• 你可以参考下这个问题的回答, 看看是否对你有帮助, 链接: https://ask.csdn.net/questions/7518765