将PHP变量设置为MySQL行中的最新值

I searched old questions, but couldn't find an answer or wrap my head around anything relevant (new to PHP and MySQl so take it easy)!

I have a MySQL table with the columns: id, subid, name; I ran this query:

CREATE TABLE mytable (id int(999999) NOT NULL auto_increment,subid varchar(99) NOT NULL,name varchar(99) NOT NULL,PRIMARY KEY (id),UNIQUE id (id),KEY id_2 (id))

From the value in subid on the latest row I want to set to $latestsubid, this is what I've managed to throw together:

    <?
    $user="me";
    $password="blah";
    $database="mydb";
    $host="localhost";
    mysql_connect($host,$user,$password);
    @mysql_select_db($database) or die( "Unable to select database");
    $query="SELECT subid FROM mytable";
    $result=mysql_query($query);
    $num=mysql_numrows($result);
    mysql_close();
    ?>

If anyone could give me a hand it'd be great!

I'm not sure if i understand what you want to achieve, but if you want to get the "subid" column value from the table row with the highest "id" value you can do:

$query="SELECT subid FROM mytable ORDER BY id DESC LIMIT 1";
$result=mysql_query($query);
$row = mysql_fetch_assoc($result);
$latest_subid = $row['subid'];

This will sort the table descending on id (so the first row returned is the one with the highest id) and then just limit your result to 1 row,

Perhaps you need can find the subid for the row with the greatest id:

$query = "SELECT subid FROM mytable ORDER BY id DESC LIMIT 1";

$result = mysql_query($query) or trigger_error(mysql_error());

while ($row = mysql_fetch_assoc($result)) {
    $latestsubid = $row["subid"];
}

This assumes that your ids are always increasing.

One-liner:

$subid = mysql_result(mysql_query("SELECT subid FROM mytable ORDER BY id DESC LIMIT 1"),0);