我的思路如下:
1、用两个input来获取年龄和退休年龄;
2、用退休年龄减去年龄计算得出要工作的年数;
3、判断要工作的年数是否大于0,大于0则打印工作年数,然后计算到哪一年退休;如果要工作的年数小于等于0,则提示可以退休了。
代码如下:
参考链接:
https://jingyan.baidu.com/article/0964eca21fd2a3c384f53612.html
Python time.localtime()用法及代码示例 - 纯净天空
import time
age = int(input("What is your current age? ")) #获取年龄
retireAge = int(input("At what age would you like to retire? ")) #获取退休年龄
workTime = retireAge-age #退休年龄减去年龄即还需要工作的年数
if workTime>0: #如果工作的年数大于0,则打印还要工作多少年,到哪一年退休
print("You have "+str(workTime)+" years left until you can retire.") #打印还要工作多少年
#https://jingyan.baidu.com/article/0964eca21fd2a3c384f53612.html
#https://vimsky.com/examples/usage/python-time-localtime-method.html
localtime = time.localtime(time.time()) #获取系统时间对象
thisYear = localtime[0] #从系统时间对象中的年份
retireYear = thisYear + workTime #退休年份即今年加上工作的年数
print("It's "+str(thisYear)+", so your can retire in "+str(retireYear)+".") #打印退休年龄
else : #如果工作年数小于等于0,则提示可以退休了
print("You can retire now.")
from datetime import datetime
currentAge = int(input("What is your current age? "))
retireAge = int(input("At what age would you like to retire? "))
thisYear = datetime.today().year
d = retireAge-currentAge
if d<0:
print("You should have retired now.")
else:
print(f"You have {d} years left until you can retire.")
print(f"It's {thisYear}, so you can retire in {thisYear+d}")