In php you often check if the object you get is of the correct type. If not you throw an exception with a message like this:
use My\Class\MyClass
...
if (!$object instanceof MyClass) {
throw new Exception(
sprintf(
"object must be of type '%s'",
'My\Class\MyClass'
)
);
}
Right now I pass the full namespace and the name of the class in a string to sprintf.
How can I get this from the class reference so that i can do something like this
sprintf("object must be of type '%s'", MyClass::getName())
EDIT:
I would like to achieve this for all classes without adding new methods. So it should be a solution using some existing method or one of the php __ MAGIC__ methods.
As of php 5.5 there's a magic constant that gives you the FQCN of any class. You can use it like this:
namespace My\Long\Namespace\Foo\Bar;
MyClass::class;
// will return "My\Long\Namespace\Foo\Bar\MyClass"
It's documented on the new features page.
namespace test;
class a {
public function getname()
{
return __CLASS__;
}
}
And:
$a = new a();
echo $a->getname(); //
Outputs
test\a
Static method works same way:
public static function getname()
{
return __CLASS__;
}
...
a::getname(); // test\a
You can also get only namespace with __NAMESPACE__
Update: you can you ReflectionClass for same thing:
$a = new a();
$r = new \ReflectionClass($a);
echo $r->getName(); // test\a
you can create ClassHelper class to have it for using anywhere you need it easily:
class ClassHelper
{
public static function getFullQualifiedName($object)
{
$rc = new \ReflectionClass($object);
return $rc->getName();
}
}
And use it:
echo ClassHelper::getFullQualifiedName($a); // test\a
Finnaly: if you use php 5.6 and above (for future), you can work with class constant
echo a::class; // test\a