Python单链表 不知道如何修改

第22行提示'Node ' object has no attribute 'next'
万分感谢

我觉得你的DeleteElementInTail写的不对。我帮你重写了一下，运行没有问题。

代码如下，如果对你有帮助，望采纳

class Node:
    def __init__(self, data):
        self.data = data
        self.next = None


class SingleLinkedList:
    def __init__(self):
        self.head = Node(None)

    def IsEmpty(self):
        if self.head.next is None:
            print("当前单列表为空")

    def InsertElementIn(self, n):
        n.next = self.head.next
        self.head.next = n

    def VisitElement(self, n):
        if n:
            print(n.data, '->', end='')

    def TraverseElement(self):
        cNode = self.head
        while cNode:
            cNode = cNode.next
            self.VisitElement(cNode)

    def DeleteElementInTail(self):
        cNode = self.head
        while True:
            if cNode.next.next is None:
                break
            cNode = cNode.next
        del cNode.next
        cNode.next = None


if __name__ == "__main__":
    lst = SingleLinkedList()
    lst.IsEmpty()
    lst.InsertElementIn(Node(1))
    lst.InsertElementIn(Node(2))
    lst.InsertElementIn(Node(3))
    lst.TraverseElement()
    print()
    lst.DeleteElementInTail()
    lst.TraverseElement()
    print()
    lst.DeleteElementInTail()
    lst.TraverseElement()