PHP语言与数据库建立连接,使用form表单进行提交,却无法获取id的值
html>
<html>
<head>
<meta charset="utf-8">
<title>员工信息更新页面title>
<style type="text/css">
*{
margin: 0px;
padding: 0px;
}
div{
border:2px solid aquamarine;
width:450px;
height:350px;
margin: 0px auto;
margin-top: 150px;
}
p{
text-align: center;
background-color: aquamarine;
font-size: 20px;
color: black;
}
.instr{
vertical-align: top;
}
form{
margin-top: 25px;
}
table{
margin-left: 5px;
}
td{
text-align:center;
}
textarea{
width: 160px;
height: 100px;
}
input{
margin: 0px auto;
margin-top: 5px;
}
style>
head>
<body>
<div>
<p>更新员工信息p>
<form action="BigProjectDBUpdateOK.php" method="get">
<table>
<tr>
<td><input type="text" name="id" value="$arr['id']?>" placeholder="请输入您想要修改的编号">
<br />
td>
tr>
table>
<table>
<tr>
<td>姓 名:td>
<td><input type="text" name="name" value="$arr['name']?>" placeholder="请输入您想要修改的真实姓名">
<br />
td>
tr>
table>
<table>
<tr>
<td>所属部门:td>
<td><input type="text" name="dept" value="$arr['dept']?>" placeholder="请输入您想要修改的所属部门">
<br />
td>
tr>
table>
<table>
<tr>
<td>出生日期:td>
<td><input type="text" name="birth" value="$arr['birth']?>" placeholder="请输入您想要修改的出生日期">
<br />
td>
tr>
table>
<table>
<tr>
<td>入职时期:td>
<td><input type="text" name="worktime" value="$arr['worktime']?>" placeholder="请输入您想要修改的入职时期">
br>
td>
tr>
table>
<table>
<td>
<a href="BigProjectDBUpdateOK.php"><input type="submit" name="submit" value="修改"/>a>
td>
table>
form>
div>
body>
html>
'localhost','root','root','phptest');
$id=$_GET['id'];
echo $id;
$name=$_GET['name'];
//echo $name;
$dept=$_GET['dept'];
//echo $dept;
$birth=$_GET['birth'];
//echo $birth;
$worktime=$_GET['worktime'];
//echo $entry;
$query="UPDATE `employee` SET `name`='$name',`dept`='$dept',`birth`='$birth',`worktime`='$worktime' WHERE `id`=$id";
// UPDATE `employee` SET `姓名`=[value-2],`所属部门`=[value-3],`出生日期`=[value-4],`入职时间`=[value-5] WHERE 1
echo $query;
/* $res=mysqli_query($link,$query);
if($res){
echo "